2×2列聯表中的SQL構建

Question

我試圖構建如下下面的鏈接解釋一個2x2列聯表：

Ad hoc 2x2 contingency tables SQL Server 2008 （試圖理解的代碼，但不能換我的頭周圍）

一個循環用於構造C1，C1 C1，C2 C2，C1 C2，C2中的對。 （笛卡爾積）

這些對是作爲sql代碼的參數給出的。對於這個例子，我已經給出了一對sql代碼 - > C1，C1當爲不同的對構造它們時，它們是正確的，如C1，C2 C2，C1（經過下面的一些修改後）。當成對C1，C1或C2，C2時，它會構造一個錯誤的應變表。

例如（表名是alpha_occurence）：

id concept_uri document_uri 

1  C1  D1 

2  C2  D1 

在對C1，C1應該從上面給定的表得到的2×2列聯表：

 C1  not C1 
    C1 1  0 
not C1 0  - 

但是，相反，得到（後一些修改）：

 C1 not C1 
    C1 0 1 
not C1 1 - 

注意我已經把一個 - 的價值不是C1，不是C1。因爲要計算使用其他方法。

這個SQL代碼用來檢索值：

SELECT count(*) AS total FROM 
(SELECT document_uri,count(DISTINCT concept_uri) AS count_conc FROM mydb.alpha_occurence 
WHERE concept_uri IN ('C1','C1') 
GROUP BY document_uri 
HAVING count_conc >=2) 
AS amount_of_concept_co_occurence #value of both X and Y 

UNION ALL 

SELECT count(*) AS total FROM 
(SELECT concept_uri,document_uri FROM mydb.alpha_occurence 
WHERE concept_uri IN ('C1')) 
AS only_concept_A #value of Only X not Y 

UNION ALL 

SELECT count(*) AS total FROM 
(SELECT concept_uri,document_uri FROM mydb.alpha_occurence 
WHERE concept_uri IN ('C1')) 
AS only_concept_B #value of Not X only Y 

檢索一個小腳本運行在這些值予以糾正值後。 以下完成：

To get Only X and not Y   = only_concept_A - amount_of_concept_co_occurence 
To get Not X and Only Y   = Only_concept_B - amount_of_concept_co_occurence 
To get the value of neither X or Y = total # of documents (which is not given here as the sample data only has data of which concept occurce in which document) - (amount_of_concept_co_occurence + Only X and not Y + Not X and Only Y) 

Answer 1

我用這個腳本

select concept_uri, document_uri, count(*) as count 
from table 
group by concept_uri, document_uri 

，他們準備..