逐行顯示的行明智

Question

使用SQL Server 2000

table1的

ID Value 

101 100 
102 200 
103 500 

我只有3排在表格中。我想在行方向視做

預期輸出

101 102 103 
100 200 500 

如何使上述條件的選擇查詢。

需要查詢幫助

Answer 1

如果您defenitely知道哪些值你在ID列，您可以使用這樣的查詢：

SELECT 
    MAX(id_101) AS id_101, 
    MAX(id_102) AS id_102, 
    MAX(id_103) AS id_103 
FROM (
SELECT 
    1 AS aux, 
    CASE WHEN ID = 101 THEN val ELSE null END AS id_101, 
    CASE WHEN ID = 102 THEN val ELSE null END AS id_102, 
    CASE WHEN ID = 103 THEN val ELSE null END AS id_103 
FROM table1 
) AS t(aux, id_101, id_102, id_103) 
GROUP BY t.aux; 

Answer 2

假設101，102，103是列名，你可以旋轉表usign PIVOT：

SELECT * 
FROM 
(
SELECT id, value 
FROM @data1 
) p 
PIVOT (SUM(value) FOR [id] IN ([101], [102], [103])) AS pvt 

---

準備數據：

DECLARE @data1 TABLE(id int, value INT) 
INSERT INTO @data1 VALUES(101, 100) 
INSERT INTO @data1 VALUES(102, 200) 
INSERT INTO @data1 VALUES(103, 500)