我希望根據第一條的規定,將按照下面三條不同欄目劃分的僱主分類。他們在完成課程的日子裏,使用數據庫列lrn_complt
告訴沒有。天的拍攝:如何根據條件將僱主分爲三列?
沒有EMP是誰完成了
0-30days 30-60days 60-90days
1st column 2nd column 3rd column
軌道不需要對SQL本或者你可以說邏輯也可能會有所幫助???
我希望根據第一條的規定,將按照下面三條不同欄目劃分的僱主分類。他們在完成課程的日子裏,使用數據庫列lrn_complt
告訴沒有。天的拍攝:如何根據條件將僱主分爲三列?
沒有EMP是誰完成了
0-30days 30-60days 60-90days
1st column 2nd column 3rd column
軌道不需要對SQL本或者你可以說邏輯也可能會有所幫助???
您需要發佈創建表和插入語句,以便任何人正確理解您的問題。您的輸入表,數據和預期輸出以及您的目標RDBMS至少。
http://tkyte.blogspot.com/2005/06/how-to-ask-questions.html
假設你有兩列這樣的...
您可以嘗試像下面嵌入式查詢...
Select id,
(select count(*) from courses where days between 0 and 30) 0_to_30_days,
(select count(*) from courses where days between 31 and 60) 0_to_30_days
(select count(*) from courses where days between 61 and 90) 0_to_30_days
from courses;
基本上,你需要做一個內部的子查詢3主查詢:
SELECT
(SELECT COUNT(*) FROM EMPLOYER WHERE LRN_COMPLT BETWEEN 0 AND 30) AS COLUMN1,
(SELECT COUNT(*) FROM EMPLOYER WHERE LRN_COMPLT BETWEEN 31 AND 60) AS COLUMN2,
(SELECT COUNT(*) FROM EMPLOYER WHERE LRN_COMPLT BETWEEN 61 AND 90) AS COLUMN3
FROM DUAL
看起來像是需要一個PIVOT
。
Select id,
COUNT(CASE WHEN lrn_complt between 0 and 30 THEN 1 END) Group1,
COUNT(CASE WHEN lrn_complt between 31 and 60 THEN 1 END) Group2,
COUNT(CASE WHEN lrn_complt between 61 and 90 THEN 1 END) Group3
from courses;
您正在使用哪個數據庫? – 2011-05-09 20:52:50
nexus teratom,並與SQL一起工作 – Mohammad 2011-05-09 21:08:42