提高SQL查詢速度

我使用MySQL和我有一樣的模式：提高SQL查詢速度

|------------|-------------|------------|--------------| 
| cities |category_city| categories| companies | 
|------------|-------------|------------|--------------| 
|  id  | city_id |  id  |  id  | 
| name | category_id | name |subcategory_id| 
|   |    | parent_id | city_id | 
|   |    |   |...other cols | 
|____________|_____________|____________|______________|

關係：市同類別有->belongsToMany()

public function categories() 
{ 
    return $this->belongsToMany(Category::class); 
}

類別有子類別：

public function subcategories() 
{ 
    return $this->hasMany(Category::class, 'parent_id', 'id'); 
}

我從類別和城市篩選公司，因爲我需要當前的城市公司和我有一個全局範圍：

public function getCompanies($city_id) 
    { 
     return $this->companies()->whereHas('mainCity', function ($q) use ($city_id) { 
      $q->where('city_id', $city_id); 
     }); 
    }

mainCity方法：

public function mainCity() 
{ 
    return $this->belongsTo(City::class, 'city_id'); 
}

這裏是我的方法執行與AJAX請求查詢：

public function getPlaces(City $city, Category $subcategory, $north, $south, $east, $west) 
{ 
    $companies = $subcategory->companies() 
     ->withCount('comments') 
     ->companiesByBounds($north, $south, $east, $west) 
     ->paginate(8); 

    $markers = $subcategory->companies() 
     ->companiesByBounds($north, $south, $east, $west) 
     ->get(['lat', 'lng', 'slug', 'title']); 

    return response()->json(['companies' => $companies, 'markers' => $markers], 200, [], JSON_NUMERIC_CHECK); 
}

和byByBounds示波器方法：

public function scopeCompaniesByBounds($query, $north, $south, $east, $west) 
{ 
    return $query->whereBetween('lat', [$south, $north]) 
     ->whereBetween('lng', [$west, $east]); 
}

在公司我有~2m記錄。主要問題是查詢花費3.5秒。請幫助改善我的疑問。

下面是該查詢：

select count(*) as aggregate from `companies` where `companies`.`category_id` = '40' and `companies`.`category_id` is not null and `lat` between '53.68540097020851' and '53.749703253622705' and `lng` between '91.34262820463869' and '91.51600619536134'

來源

2017-05-04 pwnz22

您是否嘗試過使用EXPLAIN/Visual Explain運行結果SQL來查看執行計劃？ –

不，我沒有。我怎樣才能做到這一點？ – pwnz22

我並不熟悉laravel，所以不知道如果http://stackoverflow.com/questions/18236294/how-do-i-get-the-query-builder-to-output-its-raw-sql- query-as-a-string將會爲你提供實際的SQL查詢。如果是這樣，那麼https://dev.mysql.com/doc/refman/5.7/en/explain.html展示瞭如何使用EXPLAIN，並且MySQL Workbench中的某處是Visual Explain。 –

要提高，你需要在列lat和lng添加索引的速度。

CREATE INDEX idx_lat ON companies (lat);

當列添加到條件時，索引用於查詢中。

來源

2017-05-04 07:18:06 StanislavL

提高SQL查詢速度

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