4
我在使用這段特定的代碼時遇到了問題: 虛擬函數似乎不像我期望的那樣工作。虛擬函數和向量迭代器
#include <cstdio>
#include <string>
#include <vector>
class CPolygon
{
protected:
std::string name;
public:
CPolygon()
{
this->name = "Polygon";
}
virtual void Print()
{
printf("From CPolygon: %s\n", this->name.c_str());
}
};
class CRectangle: public CPolygon
{
public:
CRectangle()
{
this->name = "Rectangle";
}
virtual void Print()
{
printf("From CRectangle: %s\n", this->name.c_str());
}
};
class CTriangle: public CPolygon
{
public:
CTriangle()
{
this->name = "Triangle";
}
virtual void Print()
{
printf("From CTriangle: %s\n", this->name.c_str());
}
};
int main()
{
CRectangle rect;
CTriangle trgl;
std::vector<CPolygon> polygons;
polygons.push_back(rect);
polygons.push_back(trgl);
for (std::vector<CPolygon>::iterator it = polygons.begin() ; it != polygons.end(); ++it)
{
it->Print();
}
return 0;
}
我期望看到:
From CRectangle: Rectangle
From CTriangle: Triangle
,而不是我得到:
From CPolygon: Rectangle
From CPolygon: Triangle
這是預期的行爲?我應該如何調用Print()函數來獲得我期望的輸出結果?
謝謝!它的工作,我也嘗試過與標準指針的例子,工作得很好。 – mpestkow
什麼是shared_ptr <>和auto?[初學] – Dineshkumar
@Dineshkumar:這是一個廣泛的話題,我建議你在StackOverflow上問一個新問題(不,兩個新問題!:))(但是別忘了做一些研究首先,答案可能已經在那裏) –