位圖大小超過虛擬機預算

Question

我已閱讀關於此問題的這些帖子，但我的情況是有點不同，因爲我不顯示位圖，但只是從原始數據後處理圖像。 首先，我打電話ImageProcessing.rgbToBitmap(data,width, height);這將返回一個位圖對象。然後我分別執行這3個功能。

1. 旋轉位圖
2. 添加水印重疊的位圖
的右下角

所有3種方法被稱爲將創建一個回報的位圖對象，它可能會導致爲位圖

添加日期崩潰，因爲我試圖每1000毫秒保存一個圖像！有時保存的圖像可能由於內存錯誤而失真。

我在下面發佈我的代碼，非常感謝您的任何建議。我不想在拍攝的圖像質量上妥協。 （需要保持分辨率）

public static Bitmap addWatermark(Resources res, Bitmap source) { 
     int w, h; 
     Canvas c; 
     Paint paint; 
     Bitmap bmp, watermark; 

     Matrix matrix; 
     float scale; 
     RectF r; 

     w = source.getWidth(); 
     h = source.getHeight(); 

     // Create the new bitmap 
     bmp = Bitmap.createBitmap(w, h, Bitmap.Config.RGB_565); 

     paint = new Paint(Paint.ANTI_ALIAS_FLAG | Paint.DITHER_FLAG 
       | Paint.FILTER_BITMAP_FLAG); 

     // Copy the original bitmap into the new one 
     c = new Canvas(bmp); 
     c.drawBitmap(source, 0, 0, paint); 

     // Load the watermark 
     watermark = BitmapFactory.decodeResource(res, R.drawable.watermark); 
     // Scale the watermark to be approximately 10% of the source image 
     // height 
     scale = (float) (((float) h * 0.80)/(float) watermark.getHeight()); 

     // Create the matrix 
     matrix = new Matrix(); 
     matrix.postScale(scale, scale); 
     // Determine the post-scaled size of the watermark 
     r = new RectF(0, 0, watermark.getWidth(), watermark.getHeight()); 
     matrix.mapRect(r); 
     // Center watermark 
     matrix.postTranslate((w - r.width())/2, (h - r.height())/2); 

     // Draw the watermark 
     c.drawBitmap(watermark, matrix, paint); 
     // Free up the bitmap memory 
     watermark.recycle(); 

     return bmp; 
    } 

public static Bitmap addDate(Bitmap src, String date) { 
     int w = src.getWidth(); 
     int h = src.getHeight(); 
     //Bitmap result = Bitmap.createBitmap(w, h, src.getConfig()); 
     Bitmap result = src; 
     Canvas canvas = new Canvas(result); 
     canvas.drawBitmap(src, 0, 0, null); 

     Paint paint = new Paint(); 
     paint.setColor(Color.rgb(255, 185, 15)); 
     paint.setTextSize(20); 
     paint.setAntiAlias(true); 
     canvas.drawText(date, w - 200, h - 20, paint); 

     return result; 
    } 
public static Bitmap rotate(Bitmap src, int rotation) { 

     int width = src.getWidth(); 
     int height = src.getHeight(); 

     // create a matrix for the manipulation 
     Matrix matrix = new Matrix(); 
     // rotate the Bitmap 
     matrix.postRotate(rotation); 

     // recreate the new Bitmap, swap width and height and apply 
     // transform 
     Bitmap rotatedBitmap = Bitmap.createBitmap(src, 0, 0, width, height, 
       matrix, true); 
     return rotatedBitmap; 

    } 

Answer 1

請先嚐試： 變化

// Copy the original bitmap into the new one 
c = new Canvas(bmp); 
c.drawBitmap(source, 0, 0, paint); 

與

// Copy the original bitmap into the new one 
c = new Canvas(bmp); 
bmp.recycle(); //here or below 
c.drawBitmap(source, 0, 0, paint); 
//below bmp.recycle(); 

這裏：

canvas.drawText(date, w - 200, h - 20, paint); 

return result; 

與

canvas.drawText(date, w - 200, h - 20, paint); 
result.recycle(); 
return result; 

這裏

Bitmap rotatedBitmap = Bitmap.createBitmap(src, 0, 0, width, height, 
       matrix, true); 
return rotatedBitmap; 

與

Bitmap rotatedBitmap = Bitmap.createBitmap(src, 0, 0, width, height, 
       matrix, true); 
return rotatedBitmap; 
rotatedBitmap.recycle(); 

添加這一切（再循環（）;），也許這已經足夠了，也嘗試代碼較小的位圖，帶看它是否仍然崩潰（像50px乘50px）。

不，他們沒有辦法增加手機的虛擬機。