C++代碼的說明

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我目前正在開發一個程序，輸出第一位數字大於最後一位的三位整數的數字1089（即幻數）。我輸入了一些代碼，但沒有收到1089，而是收到891.有沒有人可以提供一些解釋爲什麼。C++代碼的說明

//Uses a cout to inform user will be using the number 412 as an example. 
     //Uses a cout to explain to user the number needs to be reversed. 
     cout << "Alright, let's walk through an example, using the number 412." << endl; 
     int numExample = 412; 
     cout << "Please input 412" << endl; 
     cin >> numExample; 
     cout << "First, the number 412 is reversed." << endl; 
     //The following is done for reversing the number 412: 
      int reverseNum = 0, remainder = 0; 
      while (numExample) 
      { 
       remainder = numExample % 10; 
       reverseNum = (reverseNum * 10) + remainder; 
       numExample = numExample/10; 
      } 
       cout << "The reverse of 412 is " << reverseNum << endl; 
     cout << "Next, we want to subtract the reverse of the original number from its reverse" << endl; 
     cout << "This gives us 198" << endl; 
     cout << "From there, we want to reverse 198." << endl; 
     //The same procedure is used to reverse 198 
     int numExample2 = 198; 
     cout << "Please enter 198" << endl; 
     cin >> numExample2; 
      int reverseNum2 = 0, remainder2 = 0; 
      while (numExample2) 
      { 
       remainder2 = numExample2 % 10; 
       reverseNum2 = (reverseNum2 * 10) + remainder2; 
       numExample2 = numExample2/10; 
      } 
     cout << "The reverse of 198 is " << reverseNum2 << endl; 
     int magicNumber = (reverseNum2 + numExample2); 
     cout << "Following that, we want to add 891 to 189 which gives us " << magicNumber << endl;

來源

2016-02-19 Catherine Meyer

提示：while（numExample2）'循環後'numExample2'的值是多少？（如果你不知道，打印它。） – molbdnilo

我相信我在上面定義了它，但是'numExample2'是一個int，等於198. –

真的嗎？在打印「reverseNum2」後立即添加'cout << numExample2 << endl;'。想想更多關於循環結束的原因。 – molbdnilo

試着寫一個函數來處理這使你的代碼更乾淨（這也將使人們更容易幫助你！）

#include <iostream> 
#include <cmath> 
using namespace std; 

int reverseDigit(int num); // For example purposes 

int _tmain(int argc, _TCHAR* argv[]) 
{ 
    int Number1, 
    Number2, 
    temp1, 
    temp2, 
    Result; 

    cout << "Enter the number 412: "; 
    cin >> Number1; 

    temp1 = reverseDigit(Number1); 

    temp1 = Number1 - temp1; 

    cout << "Enter the number 198: "; 
    cin >> Number2; 

    temp2 = reverseDigit(Number2); 

    Result = temp1 + temp2; 

    cout << "The magic number is: " << Result << endl; 

    return 0; 
} 

int reverseDigit(int num) 
{ 
    int reverseNum = 0; 
    bool isNegative = false; 

    if (num < 0) 
    { 
     num = -num; 
     isNegative = true; 
    } 

    while (num > 0) 
    { 
     reverseNum = reverseNum * 10 + num % 10; 
     num = num/10; 
    } 

    if (isNegative) 
    { 
     reverseNum = -reverseNum; 
    } 

    return reverseNum; 
}

我知道你不否定這樣的工作如果你選擇使用這個，你可以刪除那個位，你也可以擴展它......這就是說，這將使實際的「反轉過程」更容易處理和改進和閱讀。

來源

2016-02-19 18:19:11 suroh

@molbdnilo或者只是做得更好，寫一個函數，讓你不會迷失在自己的工作中！（請注意：你和你的使用是一般性的，而不是針對你個人，而是針對任何閱讀評論的人。） – suroh

C++代碼的說明

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