在angularjs

Question

我有兩個tables.College_Infra_items和College_infrastructure.The College_Infra_items有以下結構

col_infraId requiredSeat available  collegeInfrastructureId 
     1   100    150     1 
     2   200    180     2 

College_infrastructure有以下結構上裝載

collegeInfrastructureId type name 
     1     UGC  Land Requirement(In acres) 
     2     UGC  Class rooms 
     3     AICTE Total Area 
     4     AICTE Loans 

現在，在我的html我是在重複顯示多表數據College_infrastructure詳細信息。 我正在寫類型的條件。也就是說，如果它是UGC類型，那麼College_infrastructure的前兩行細節將加載。如果AICTE接下來兩個。 這裏是我的html

在表格格式中，我顯示detailss.tbody節我重複College_infrastructure表只爲「名稱」列。但我無法得到requiredSeat的詳細信息，因爲在查詢中我沒有執行與College_infraItem表連接操作。

<tbody> 
    <tr role="row" class="even" data-ng-repeat="infraitem in 
    allInfraitemsByType"> 
    <td><strong>{{infraitem.name}}</strong></td> 
    <td><input type="text" 
    name="requiredseat" data-ng-model="infraitem.requiredseat"></td> 
    <td> 
    <input type="text" name="available" data-ng- 
    model="infraitem.available"></td> 
    <td class="text-center"><button type="submit" class="btn GreenBtn" 
    data-ng-click="saveInfrastructureDetails(infraitem)"><span 
    class="glyphicon glyphicon-ok"></span>Save</button></td> 
    </tr> 
    </tbody> 

查詢我寫這樣的

SELECT collegeInfrastructureId as collegeInfrastructureId,type as 
    type,name as name FROM college_infrastructure where type=:type 
    order by collegeInfrastructureId asc"; 

此查詢僅給了我College_Infrastructure table.But我想也是在同一查詢College_Infra_items的細節。 任何人都可以告訴我如何加入College_Infra_items這個查詢，以便在HTML重複我也可以參考College_Infra_items列。

Answer 1

SELECT ci.collegeInfrastructureId as collegeInfrastructureId,ci.type as 
type,ci.name as name , 
    cli.requiredSeat 
    ... and some more fields you need 
FROM college_infrastructure ci 
    LEFT JOIN College_Infra_items cli ON cli.collegeInfrastructureId=ci.collegeInfrastructureId 
where type=:type 
order by ci.collegeInfrastructureId asc"; 

只需在您的查詢中使用INNER JOIN作爲第二個表。

UPDATE。更改INNER JOIN到LEFT JOIN

Answer 2

試試這個：

SELECT college_infrastructure.collegeInfrastructureId as collegeInfrastructureId,college_infrastructure.type as type,college_infrastructure.name as name ,College_Infra_items.requiredSeat 
FROM college_infrastructure left join College_Infra_items on College_Infra_items.collegeInfrastructureId = college_infrastructure.collegeInfrastructureId 
where type=:type 
order by collegeInfrastructureId asc";