C＃服務器和Androiod客戶端

Question

我正在開發兩個程序，一個是運行服務器和第二個程序的Microsoft Visual Studio 2010軟件：Eclipse ADT（ANDROID設備開發環境），我認爲它是客戶端。目標是在C＃中的SERVER和Android CLIENT之間建立連接。它不應該是一個問題，我試圖在TCP和UDP嘗試，它落在對象創建上下文（在落在對象套接字的TCP和UDP SOCKET落入DATAGRAM對象創建），在我看來，問題是：activitythread .performlaunchactivity（activitythread $ activityclientreco rd intent）line 2247

據我所知，問題不在於我的代碼片段，而是在Eclipse中內置SOCKET補充軟件，我嘗試重新安裝，添加最新的插件。針對您的下一個問題，我爲Android設備和互聯網設置了權限。這我不知道如何處理這個問題，我打算一個月或更多..

在additiong我會在Android客戶端添加我的代碼：

import android.app.Activity; 
import android.os.Bundle; 
import android.view.View; 
import android.widget.Button; 
import android.widget.TextView; 

import java.io.BufferedReader; 
import java.io.BufferedWriter; 
import java.io.IOException; 
import java.io.InputStream; 
import java.io.OutputStreamWriter; 
import java.io.InputStreamReader; 
import java.io.PrintWriter; 
import java.net.InetAddress; 
import java.net.Socket; 
import java.net.UnknownHostException; 

import android.util.Log; 

public class MainActivity extends Activity { 
private TextView txt; 
private Button b; 

@Override 
public void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState); 
    setContentView(R.layout.activity_main); 
    b = (Button)findViewById(R.id.button1); 
    txt = (TextView)findViewById(R.id.textView1); 


    b.setOnClickListener(new View.OnClickListener() { 

     @Override 
     public void onClick(View v) { 
      // TODO Auto-generated method stub 
     connectSocket("Hello"); 

     } 
    }); 
} 

private void connectSocket(String a){ 

    try { 
     InetAddress serverAddr = InetAddress.getByName("10.0.0.8"); 
     Log.d("TCP", "C: Connecting..."); 
     **Socket socket = new Socket(serverAddr, 4444);** 

     String message = "1"; 

     PrintWriter out = null; 
     BufferedReader in = null; 

     try { 
      Log.d("TCP", "C: Sending: '" + message + "'"); 
      out = new PrintWriter(new BufferedWriter(new OutputStreamWriter(socket.getOutputStream())),true); 
      in = new BufferedReader(new InputStreamReader(socket.getInputStream()));     

      out.println(message); 
      while ((in.readLine()) != null) { 
       txt.append(in.readLine()); 
      } 

      Log.d("TCP", "C: Sent."); 
      Log.d("TCP", "C: Done.");    

     } catch(Exception e) { 
      Log.e("TCP", "S: Error", e); 
     } finally { 
      socket.close(); 
     } 

    } catch (UnknownHostException e) { 
     // TODO Auto-generated catch block 
     Log.e("TCP", "C: UnknownHostException", e); 
     e.printStackTrace(); 
    } catch (IOException e) { 
     // TODO Auto-generated catch block 
     Log.e("TCP", "C: IOException", e); 
     e.printStackTrace(); 
    }  
} 
} 

和我在C＃中的服務器：

using System; 
using System.Text; 
using System.Collections.Generic; 
using System.Linq; 
using System.Net; 
using System.Net.Sockets; 

public class TestTCP 
{ 
    public static void Main() 
    { 
     try 
     { 
      IPAddress ipAd = IPAddress.Parse("127.0.0.1"); 
      // use local m/c IP address, and 

      // use the same in the client 


      /* Initializes the Listener */ 
      TcpListener myList = new TcpListener(ipAd, 11000); 

      /* Start Listeneting at the specified port */ 
      myList.Start(); 

      Console.WriteLine("The server is running at port 11000..."); 
      Console.WriteLine("The local End point is :" + 
           myList.LocalEndpoint); 
      Console.WriteLine("Waiting for a connection....."); 
     m: 
      Socket s = myList.AcceptSocket(); 
      Console.WriteLine("Connection accepted from " + s.RemoteEndPoint); 

      byte[] b = new byte[100]; 
      int k = s.Receive(b); 

      char cc = ' '; 
      string test = null; 
      Console.WriteLine("Recieved..."); 
      for (int i = 0; i < k - 1; i++) 
      { 
       Console.Write(Convert.ToChar(b[i])); 
       cc = Convert.ToChar(b[i]); 
       test += cc.ToString(); 
      } 

      switch (test) 
      { 
       case "1": 
        break; 


      } 

      ASCIIEncoding asen = new ASCIIEncoding(); 
      s.Send(asen.GetBytes("The string was recieved by the server.")); 
      Console.WriteLine("\nSent Acknowledgement"); 


      /* clean up */ 
      goto m; 
      s.Close(); 
      myList.Stop(); 
      Console.ReadLine(); 

     } 
     catch (Exception e) 
     { 
      Console.WriteLine("Error..... " + e.StackTrace); 
     } 
    } 

} 

謝謝。

Answer 1

首先，您可能不會在您的UI線程中運行​​方法。你必須做這樣的事情：

b.setOnClickListener(new View.OnClickListener() { 

    @Override 
    public void onClick(View v) { 
     Thread stackOverflow = new Thread(new Runnable() { 

      @Override 
      public void run() { 
       connectSocket("Hello"); 

      }}); 

     stackOverflow.start(); 
    } 
}); 

否則，你得到這個異常：

android.os.NetworkOnMainThreadException 

其次，你必須連接到相同的端口和接口在您的服務器監聽：

IPAddress ipAd = IPAddress.Parse("127.0.0.1"); 

應與您在Android應用程序中使用的地址相同：

IPAddress ipAd = IPAddress.Parse("10.0.0.8"); 

和自己的Android應用程序必須連接到同一個端口，其中服務器監聽：

Socket socket = new Socket(serverAddr, 11000); 

最後不要忘了Android權限：

<uses-permission android:name="android.permission.INTERNET" /> 
    <uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" /> 

而且要小心防火牆之類的東西，他們也可能會放棄你的聯繫。