蟒蛇 - 熊貓：每

Question

行

我有一個數據幀計數相同的值，如下：

      investing.com         ft      bloomberg 
19  API Weekly Distillates Stocks         NaN         NaN 
20   API Weekly Gasoline Stock         NaN         NaN 
21         NaN   Advance Goods Trade Balance   Advance Goods Trade Balance 
22         NaN         NaN    Advance Retail Sales 
23      All Car Sales         NaN         NaN 
24      All Truck Sales         NaN         NaN 
25   Average Hourly Earnings MoM   Average Hourly Earnings MoM   Average Hourly Earnings MoM 
26         NaN         NaN   Average Hourly Earnings YoY 

我願與所有未楠值的計數添加一列。

我想：

df['count of not NaN'] = df.apply(lambda x:(x[['investing.com','ft','bloomberg']] != 'NaN').count(), axis=1)

，但沒有奏效。任何人都知道爲什麼/可以幫助我使用正確的配方？ （我知道這個問題的一些口味已經發布，但他們不能真正幫助我獲得成功的結果......） 謝謝！

Answer 1

計數方法正是這樣做的。使用axis = 1添加一列。

df.count(axis=1)