3
我有這樣的SQL查詢:如何創建使用groupby的column_properties?
select
rooms.*,
COUNT(DISTINCT(o.resident_id)) as resident_count,
COUNT(reviews.id) as review_count,
COUNT(photos.id) as photo_count,
AVG(reviews.rating) as mean_review
from
t_rooms rooms
JOIN
t_room_listings listings on listings.room_id = rooms.id
JOIN
t_occupancies o on o.listing_id = listings.id
LEFT JOIN
t_reviews reviews on reviews.occupancy_id = o.id
LEFT JOIN
t_photos photos on photos.occupancy_id = o.id
GROUP BY rooms.id
我知道我可以在ORM查詢的形式寫爲:
q = (session
.query(
Room,
func.count(func.distinct(Occupancy.resident_id)).label('resident_count'),
func.count(Review.id).label('review_count'),
func.count(Photo.id).label('photo_count'),
(
(3 + func.avg(Review.rating))/(1 + func.count(Review.rating))
).label('bayesian_rating')
)
.select_from(
join(Room, RoomListing).join(Occupancy).outerjoin(Review).outerjoin(Photo)
)
.group_by(Room.id)
)
for room, res_ct, rev_ct, p_ct in q:
wish_that_I_could_write(room.res_ct, room.rev_ct, room.p_ct, room.score)
但我怎麼能在我的Room
類中聲明resident_count
,review_count
等爲column_property
小號,所以我不需要每次都構造這個查詢?