顯示完整的行，其中一列是重複的

Question

我似乎無法知道如何找到這方面的東西。 這是我的例子顯示我只是重複的列：

select column1,COUNT(column1) 
    from table 
    where column1> 0 
    GROUP BY column1 
    HAVING COUNT(column1) > 1 

OUTPUT：

---------------------------- 
column1 | (name not defined) 
---------------------------- 
2134567 | 2 
2881992 | 3 

我要的是：

------------------------------------------------ 
column0 | column2 |column1 | (name not defined) 
------------------------------------------------ 
1  |  abc |2134567 | 2 
2  |  cde |2881992 | 3 

我怎樣才能做到這一點？

Answer 1

你需要加入查詢回要在另外的數據拉從

SELECT column0, column2, table.column1, columncount 
FROM table 
    INNER JOIN (SELECT column1, COUNT(column1) columncount 
       FROM table 
       WHERE column1> 0 
       GROUP BY column1 HAVING COUNT(column1) > 1) t2 ON table.column1 = t2.column1 

Answer 2

試試如表：

SELECT * FROM [Tanle1] 
WHERE Column0 IN 
    (SELECT Column0 FROM [Table1] 
     GROUP BY Column0 
     HAVING COUNT(Column0) > 1)