批處理腳本讀取目錄中的文件名並要求用戶選擇一個

Question

感謝您關注我的問題。

我在給定的目錄中有五個配置文件。在我的批處理腳本中，我想讀取這些文件名並將其提示給用戶。一旦用戶選擇了一個配置文件，從它讀取變量。

任何人都可以幫我在這裏的一些邏輯。所以，我可以繼續前進。

謝謝。

Answer 1

這樣的批處理文件或.cmd這樣的文件演示了菜單技術（沒什麼奇怪的，用戶必須準確輸入文件名）。關鍵項目：

FOR 
SET /P 
IF EXIST 

祝你好運！

@echo off 

REM Show the user the list and ask them which one to use 
echo. 
echo Please select one of: 
echo. 
for %%F in ("D:\A Given Directory\*.config") do echo  %%~nxF 
echo. 
set SEL_CFGFNM= 
set /P SEL_CFGFNM=Which configuration file: 

REM Make sure they answered, and that the file exists 
if "%SEL_CFGFNM%" == "" goto ENDIT 
if NOT EXIST "D:\A Given Directory\%SEL_CFGFNM%" goto NOCFG 

REM User has selected file "D:\A Given Directory\%SEL_CFGFNM%" and it exists 
REM Do whatever you want to do with that file now 

REM Don't fall through the exit messages 
goto ENDIT 

REM Exit Messages 
:NOCFG 
echo. 
echo ERROR: Configuration file "%SEL_CFGFNM%" is not on the list 
echo. 
goto ENDIT 

REM Cleanup 
:ENDIT 
set SEL_CFGFNM=