的MySQL查詢無效：嵌套選擇

Question

的過高的水平，我切換代碼安德魯斯解決方案：

SELECT s1.biz_name, s1.biz_info, s1.e_address, s1.e_city, s1.e_state, 
    s1.e_postal, s1.e_zip_full, s1.loc_LAT_centroid, s1.loc_LONG_centroid, 
    s1.biz_phone, s1.biz_phone_ext, s1.biz_fax, s1.biz_email, s1.web_url, 
    s2.upc as upc2, s2.retailprice as retailprice2, s2.dollar_sales as 
    dollar_sales2, s2.dollar_sales_ly as dollar_sales_ly2, s2.todaydate as 
    todaydate2, s2.datetimesql as datetimesql2, s2.shelfposition as 
    shelfposition2, s2.reg_sale as reg_sale2, s2.representative as 
    representative2, s2.notes as notes2, s3.upc as upc3, s3.retailprice as 
    retailprice3, s3.dollar_sales as dollar_sales3, s3.dollar_sales_ly as 
    dollar_sales_ly3, s3.todaydate as todaydate3, s3.datetimesql as 
    datetimesql3, s3.shelfposition as shelfposition3, s3.reg_sale as reg_sale3, 
    s3.representative as representative3, s3.notes as notes3, s4.upc as upc4, 
    s4.retailprice as retailprice4, s4.dollar_sales as dollar_sales4, 
    s4.dollar_sales_ly as dollar_sales_ly4, s4.todaydate as todaydate4, 
    s4.datetimesql as datetimesql4, s4.shelfposition as shelfposition4, 
    s4.reg_sale as reg_sale4, s4.representative as representative4, s4.notes as 
    notes4, s5.upc as upc5, s5.retailprice as retailprice5, s5.dollar_sales as 
    dollar_sales5, s5.dollar_sales_ly as dollar_sales_ly5, s5.todaydate as 
    todaydate5, s5.datetimesql as datetimesql5, s5.shelfposition as 
    shelfposition5, s5.reg_sale as reg_sale5, s5.representative as 
    representative5, s5.notes as notes5 
FROM allStores AS s1 
LEFT OUTER JOIN storeCheckRecords AS s2 
    ON s1.e_address = s2.e_address AND s2.upc = '650637119004' 
LEFT OUTER JOIN storeCheckRecords AS s3 
    ON s1.e_address = s3.e_address AND s3.upc = '650637119011' 
LEFT OUTER JOIN storeCheckRecords AS s4 
    ON s1.e_address = s4.e_address AND s4.upc = '650637374007' 
LEFT OUTER JOIN storeCheckRecords AS s5 
    ON s1.e_address = s5.e_address AND s5.upc = '650637374014' 
WHERE s2.e_address IS NOT NULL 
    OR s3.e_address IS NOT NULL 
    OR s4.e_address IS NOT NULL 
    OR s5.e_address IS NOT NULL 

這裏是新的錯誤：查詢無效：表過多; MySQL只能在一個連接中使用61個表格

任何其他想法？謝謝您的幫助。

Answer 1

這應該給你相同的結果，而無需使用子查詢：

SELECT s1.biz_name, 
     ... 
     s2.upc    AS upc2, 
     ... 
     s3.upc    AS upc3, 
     ... 
     s4.upc    AS upc4, 
     ... 
     s5.upc    AS upc5, 
     ... 
FROM allStores AS s1 
LEFT OUTER JOIN storeCheckRecords AS s2 ON s1.e_address = s2.e_address 
LEFT OUTER JOIN storeCheckRecords AS s3 ON s1.e_address = s3.e_address 
LEFT OUTER JOIN storeCheckRecords AS s4 ON s1.e_address = s4.e_address 
LEFT OUTER JOIN storeCheckRecords AS s5 ON s1.e_address = s5.e_address 
WHERE (s2.e_address IS NOT NULL 
OR s3.e_address IS NOT NULL 
OR s4.e_address IS NOT NULL 
OR s5.e_address IS NOT NULL) 
AND (s2.upc = '650637119004' OR s2.upc IS NULL) 
AND (s3.upc = '650637119011' OR s3.upc IS NULL) 
AND (s4.upc = '650637374007' OR s4.upc IS NULL) 
AND (s5.upc = '650637374014' OR s5.upc IS NULL) 

Answer 2

可能與 MySQL bug #41156, List of derived tables acts like a chain of mutually-nested subqueries。

的錯誤日誌表明它反對的MySQL 5.0.72，5.1.30和6.0.7驗證。
在MySQL 5.1.37，MySQL 5.4.2（成爲5.5.something）和NDB 7.1.0中修復。

---

關於上述問題的重新設計的查詢：

樞軸查詢可能會非常棘手。您可以使用Andrew在his answer中建議的方法。如果搜索許多UPC值，則需要編寫應用程序代碼來構建SQL查詢，並追加與搜索的UPC值數量相同的JOIN子句。

的MySQL確實有對聯接，可以在一個單一的查詢進行數量限制，但例如，你應該沒有達到極限。也就是說，您顯示的查詢確實有效。

我假設你正在展示一個例子查詢搜索四個UPC碼，而你的應用程序可以動態地構造查詢的UPC代碼數量更多，而且可能超過61的時候。

它看起來像您的查詢的目標是返回擁有所列出的UPC代碼的至少一個商店。你可以做更多的只是在下面的查詢：

SELECT DISTINCT s.* 
FROM allStores AS s 
JOIN storeCheckRecords AS cr 
    ON s.e_address = cr.e_address 
    AND cr.upc IN ('650637119004','650637119011','650637374007','650637374014'); 

您可以在其他方面使用這種方法，例如查找具有的UPC的所有四店：

SELECT s.* 
FROM allStores AS s 
JOIN storeCheckRecords AS cr 
    ON s.e_address = cr.e_address 
    AND cr.upc IN ('650637119004','650637119011','650637374007','650637374014'); 
GROUP BY s.e_address 
HAVING COUNT(DISTINCT upc) = 4; 

或者找到存儲了一些但不是所有四個的UPC的：

SELECT s.* 
FROM allStores AS s 
JOIN storeCheckRecords AS cr 
    ON s.e_address = cr.e_address 
    AND cr.upc IN ('650637119004','650637119011','650637374007','650637374014'); 
GROUP BY s.e_address 
HAVING COUNT(DISTINCT upc) < 4; 

或者找到商店缺乏的UPC的所有四個：

SELECT s.* 
FROM allStores AS s 
JOIN storeCheckRecords AS cr 
    ON s.e_address = cr.e_address 
    AND cr.upc IN ('650637119004','650637119011','650637374007','650637374014'); 
WHERE cr.e_address IS NULL; 

你還必須寫一些代碼來構建這個查詢，但它是一個有點容易做的，它不超過上加入或可以運行子查詢的數量的任何限制。

Answer 3

我將簡化到只得到所有的元素先用一個簡單的WHERE IN子句......你似乎是做了透視表顯示T1到T2到T3到T4至T5。如果您獲取了單個行中的所有數據，那麼您可以在頂部顯示STATIC列來顯示每個行下面的詳細信息。

SELECT 
     t1.brand, 
     t1.biz_name, 
     t1.biz_info, 
     t1.e_address, 
     t1.e_city, 
     t1.e_state, 
     t1.e_postal, 
     t1.e_zip_full, 
     t1.loc_LAT_centroid, 
     t1.loc_LONG_centroid, 
     t1.biz_phone, 
     t1.biz_phone_ext, 
     t1.biz_fax, 
     t1.biz_email, 
     t1.web_url, 
     t1.upc, 
     t1.retailprice, 
     t1.dollar_sales, 
     t1.dollar_sales_ly, 
     t1.todaydate, 
     t1.datetimesql, 
     t1.shelfposition, 
     t1.reg_sale, 
     t1.representative, 
     t1.notes 
    FROM 
     storeCheckRecords as t1 
    WHERE 
     t1.upc IN ('650637119004', '650637119011', '650637374007', '650637374014') 

等..

Brand Bus Addr     UPC  Retail$  Sales  Notes 
xyz Bus Name     UPC  ... etc... Cur Yr 
     Bus Info     Shelf Info    Last Yr 
     Address, (Cit/State/Zip) 
     Lat/Long 
     Phone/Fax 
     Email/Web 

---- 
Next Entry 

確實相同的地址是相同的，而不是誰攜帶的項目？如果一個條目是「123 Main St」，另一個是「123B Main St」，並且「123 Main St - Suite B」，那麼您將找不到匹配項。

此外，你提到了一些最多有75個UPC代碼......將它們放在一個單獨的表中，並將其作爲第一個表加入到「StoreCheckRecords」中，並將它們全部取出...而不是手動鍵入所有列後綴從2到75 ...或者在下一次運行中很多隻有17個，而另一個4 ...我認爲你可能太過於固定你試圖從數據中獲得的東西。

您甚至可以通過您最初想要基於該匹配的常見「e_address」進行GROUP，並將該組作爲報告給用戶的部分之間的中斷。