我一直在尋找這個,我總是得到答案,改變了做事的方式,但不解決一般問題,即:引用嵌套SELECT中的主要查詢變量。MySQL - 引用嵌套選擇主查詢(需要嵌套)
我需要它是一個嵌套查詢,因爲數據結構非常複雜。讓我們來看看,我需要做的例子:
SET @teamg_id := 0;
SELECT
@teamg_id := player.team_id,
player.team_id AS player_team,
event.local_team_id AS local_team,
event.visitor_team_id AS visitor_team,
action.unique_id AS action_id,
action.player_id AS player_id,
player.name AS player_name,
playerindex.rank AS player_pos,
playerindex.ses_var_nest AS ses_var_nest
FROM
er_players player,
er_events event,
er_actions action
LEFT JOIN
(SELECT
unique_id, team_id, @pn:[email protected]+1 AS rank, @teamg_id AS ses_var_nest
FROM
er_players, (SELECT @pn:=-1) p2
WHERE
team_id = @teamg_id
ORDER BY
dorsal ASC, id DESC) playerindex
ON
playerindex.unique_id = action.player_id
WHERE
action.unique_id = '1374572622'
AND player.unique_id = action.player_id
AND event.unique_id = (SELECT event_id
FROM er_analysis
WHERE unique_id = action.analysis_id)
正如你所看到的,我需要返回該球員的「指數」,在他的團隊中,爲了將它返回做查詢(排名價值),但我需要它被統計到相關的球隊,而不是整個球員表。
爲了做到這一點,我需要在嵌套的SELECT內引用主要查詢值「player.team_id」 - 我試過並且無法做到這一點,所以我最終使用了session變量。
我從此查詢得到的是@teamg_id商店以及主查詢的價值,但傳遞給嵌套查詢其值依次爲NULL時:
@teamg_id | player_team | local_team | visitor_team | action_id | player_id | player_name | player_pos | ses_var_nest
1374570040 | 1374570040 | 1374570040 | 1374571827 | 1374572622 | 1374570146 | Player name | NULL | NULL
我的問題是我怎麼能在嵌套查詢中使用會話變量 - 我認爲應該可以工作 - 或者如何引用主查詢值。
感謝您的幫助!
編輯:這裏是er_players表的結構,這是給我的問題。如果我說「給我指數」玩家3「,它應該給我2(0,1,2),因爲它是他的團隊中的第三名玩家。
+------------+------------+----------+----------+--------+
| unique_id | team_id | name | position | dorsal |
+------------+------------+----------+----------+--------+
| 1374570066 | 1374570040 | Player 1 | Defense | 1 |
| 1374570034 | 1374570040 | Player 2 | Defense | 2 |
| 1374677119 | 1374571827 | Player 7 | Position | 7 |
| 1374570146 | 1374570040 | Player 3 | Attack | 5 |
+------------+------------+----------+----------+--------+
EDIT 2(液):找到了解決由於Kordirko的答案,有的玩。
SELECT
player.team_id AS player_team,
event.local_team_id AS local_team,
event.visitor_team_id AS visitor_team,
action.unique_id AS action_id,
action.player_id AS player_id,
player.name AS player_name,
playerindex.rank AS player_pos,
playerindex.ses_var_nest AS ses_var_nest
FROM
er_actions action
LEFT JOIN er_events event
ON event.unique_id = (SELECT event_id FROM er_analysis WHERE unique_id = action.analysis_id)
LEFT JOIN er_players player
ON player.unique_id = action.player_id
LEFT JOIN
(SELECT
unique_id, team_id, team_id AS ses_var_nest ,
case when team_id <> @lastteam
then (@pn:=-1)
end AS hander,
case when team_id <> @lastteam
then(@lastteam:=team_id)
end AS team_id_new,
@pn:[email protected]+1 AS rank
FROM
er_players, (SELECT (@pn:=-1),(@lastteam:=0)) p2
ORDER BY
team_id, dorsal ASC, id DESC) playerindex
ON
playerindex.unique_id = action.player_id
AND playerindex.team_id = player.team_id /* new join condition */
WHERE
action.unique_id = '1374572622'
選擇病例後@rank使得它不爲0的兩倍,並且選擇之前將@rank復位。否則,它將變爲0,但進入每支球隊的第二位球員。
希望有人能找到有用的這個問題。
感謝Kordirko再次爲他的時間和答案。
你好Kordirko!非常感謝您的回答。我得到一個錯誤,我通過將所有表連接到主表(「er_actions」)解決了這個問題,因爲player.team_id不能被引用,因爲它是第一個表而不是JOINED表。它現在正在工作,但我不明白爲什麼,當球隊不同時,計數器不會變爲0。也許你可以找到爲什麼,因爲我無法做到這一點 - 我認爲它應該,正如你所說的那樣。再次感謝您的時間和答案! – Unapedra
我已經找到了合適的解決方案,這要感謝您的參與以及我的參與。非常感謝您的時間和幫助!沒有你的答案,我不會做到的! – Unapedra