PyQt4-> PyQt5翻譯

Question

我對錶格數據的分頁顯示感興趣。我發現這個鏈接：https://sateeshkumarb.wordpress.com/2012/04/01/paginated-display-of-table-data-in-pyqt/ 由PyQt4製作有趣的代碼。我試圖在python 3.4上的PyQt5中翻譯它。代碼如下：

import sys 
from PyQt5 import QtWidgets, QtCore 

class Person(object): 
    """Name of the person along with his city""" 
    def __init__(self,name,city): 
     self.name = name 
     self.city = city 
class PersonDisplay(QtWidgets.QMainWindow): 
    def __init__(self, parent=None): 
     super(PersonDisplay, self).__init__(parent) 
     #QtWidgets.QMainWindow.__init__(self, parent) 
     self.setWindowTitle('Person City') 
     view = QtWidgets.QTableView() 
     tableData = PersonTableModel() 
     view.setModel(tableData) 
     self.setCentralWidget(view) 
     tableData.addPerson(Person('Ramesh', 'Delhi')) 
     tableData.addPerson(Person('Suresh', 'Chennai')) 
     tableData.addPerson(Person('Kiran', 'Bangalore')) 

class PersonTableModel(QtCore.QAbstractTableModel): 
    def __init__(self): 
     super(PersonTableModel,self).__init__() 
     self.headers = ['Name','City'] 
     self.persons = ['Ramesh', 'Delhi'] 

    def rowCount(self,index=QtCore.QModelIndex()): 
     return len(self.persons) 

    def addPerson(self,person): 
     self.beginResetModel() 
     self.persons.append(person) 
     self.endResetModel() 

    def columnCount(self,index=QtCore.QModelIndex()): 
     return len(self.headers) 

    def data(self,index,role=QtCore.Qt.DisplayRole): 
     col = index.column() 
     person = self.persons[index.row()] 
     if role == QtCore.Qt.DisplayRole: 
      if col == 0: 
       return QtWidgets.QVariant(person.name) 
      elif col == 1: 
       return QtWidgets.QVariant(person.city) 
      return QtWidgets.QVariant() 

    def headerData(self,section,orientation,role=QtCore.Qt.DisplayRole): 
     if role != QtCore.Qt.DisplayRole: 
      return QtWidgets.QVariant() 

     if orientation == QtCore.Qt.Horizontal: 
      return QtWidgets.QVariant(self.headers[section]) 
     return QtWidgets.QVariant(int(section + 1)) 

if __name__ == '__main__': 
    app = QtWidgets.QApplication(sys.argv) 
    appWin = PersonDisplay() 
    appWin.show() 
    sys.exit(app.exec_()) 

這似乎是正確的，但運行停在：view.setModel（tableData）。 我不知道這是由於我的翻譯或代碼錯誤。任何想法？由於

Answer 1

1）QtWidgets.QVariant是提高了AttributeError因爲QVariant是QtCore包不QtWidgets下。

2）在PyQt5中，你不需要明確地使用QVariant，所以你可以完全刪除它們。

3）在PersonTableModel.data()，person是一個字符串，person.name和person.city將上升錯誤。

這裏一個固定的版本的PersonTableModel：

class PersonTableModel(QtCore.QAbstractTableModel): 
    def __init__(self): 
     super(PersonTableModel,self).__init__() 
     self.headers = ['Name','City'] 
     self.persons = ['Ramesh', 'Delhi'] 

    def rowCount(self,index=QtCore.QModelIndex()): 
     return len(self.persons) 

    def addPerson(self,person): 
     self.beginResetModel() 
     self.persons.append(person) 
     self.endResetModel() 

    def columnCount(self,index=QtCore.QModelIndex()): 
     return len(self.headers) 

    def data(self,index,role=QtCore.Qt.DisplayRole): 
     col = index.column() 
     person = self.persons[index.row()] 
     if role == QtCore.Qt.DisplayRole: 
      if col == 0: 
       return person 
      elif col == 1: 
       return person 
      return None 

    def headerData(self,section,orientation,role=QtCore.Qt.DisplayRole): 
     if role != QtCore.Qt.DisplayRole: 
      return None 

     if orientation == QtCore.Qt.Horizontal: 
      return self.headers[section] 
     return int(section + 1) 

附：

你的代碼是提高此異常：

Traceback (most recent call last): 
    File "test.py", line 51, in headerData 
    return QtWidgets.QVariant() 
AttributeError: module 'PyQt5.QtWidgets' has no attribute 'QVariant' 

它可能是有用的，包括在這個問題