2010-07-26 41 views
1

一個「DIV」元素的阻力,這是我的代碼,因爲某些原因,我不能使用任何JavaScript LIB,等等; jQuery的:如何使iphone

<!DOCTYPE html PUBLIC "-//WAPFORUM//DTD XHTML Mobile 1.0//EN" "http://www.wapforum.org/DTD/xhtml-mobile10.dtd"> 
<html xmlns="http://www.w3.org/1999/xhtml" style="height: 100%;"> 
    <head> 
     <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> 
     <meta name="viewport" content="width=device-width,minimum-scale=0.3,maximum-scale=5.0,user-scalable=yes"> 
     <meta name="apple-mobile-web-app-capable" content="yes" /> 
    </head> 
<body style="height: 100%;margin:0;"> 

<style type="text/css"> 
#draggable { width: 100px; height: 100px; padding: 0.5em; float: left; margin: 10px 10px 10px 0; 
    border:1px solid #DDDDDD; 
    color:#333333; 
    background:#F2F2F2; 
    cursor:move; 
    } 
#droppable { width: 150px; height: 150px; padding: 0.5em; float: left; margin: 10px; 
    border:1px solid #E78F08; 
    color:#FFFFFF; 
    font-weight:bold; 
    background:#F6A828; 
    overflow:hidden; 
    } 
#droppable.highlight{ 

    } 
#draggable.end{ 
    left:0px !important; 
    top:0px !important; 
    } 
</style> 



<div class="demo" style="margin:0 auto;height: 100%;"> 
    <div id="A" style="float:left;height:50%;margin:0 100px 0 0;width:100%;background:#333;"> 
     <div id="draggable"> 
      <p>Drag me to my target</p> 
     </div> 
    </div> 
    <div id="droppable" > 
     <p>Drop here</p> 
    </div> 
</div><!-- End demo --> 

<script type="text/javascript"> 
var $=function(id) { 
    return document.getElementById(id); 
} 

$('draggable').ontouchstart = function(evt){ 
    console.log(evt.pageX + "/" + evt.pageY); 
} 

$('draggable').ontouchmove = function(e){ 
    if(e.touches.length == 1){ // Only deal with one finger 
    var touch = e.touches[0]; // Get the information for finger #1 
    var node = touch.target; // Find the node the drag started from 
    node.style.position = "absolute"; 
    node.style.left = touch.pageX -node.offsetWidth /2+ "px"; 
    node.style.top = touch.pageX -node.offsetHeight/2+ "px"; 
    } 
} 
</script> 

</body> 
</html> 

我的代碼無法生成正確的跟蹤,

所以我能做些什麼。

感謝

回答

-1

我沒有看所有的jQuery代碼,但它看起來像你有正確的jQuery UI的功能在裏面。你說你不能使用jQuery,但你是否包含它?

嘗試添加以下代碼(在頭節)進口都來自谷歌的託管服務的jQuery和jQueryUI的庫:

<script language="JavaScript" SRC="https://ajax.googleapis.com/ajax/libs/jquery/1.5.2/jquery.min.js"> 
</script> 
<script language="JavaScript" SRC="https://ajax.googleapis.com/ajax/libs/jqueryui/1.8.11/jquery-ui.min.js"> 
    </script>