將pandas DataFrame中的對象從一個「單元格」移動到另一個「單元格」

Question

我需要將pandas DataFrame中的對象從一個位置移動到另一個位置，並將該對象的原始位置保留爲空白而不影響其他列。

employees = [0, 0, 0, 1, 0, 0, 0, 0, 0, 0] 
levels = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] 

df = pd.DataFrame({"Employees":employees, "Level":levels}) 

#move employee 1 from index 3 to index 1 without altering Level column 
#leave index 3 blank after moving employee 1 

在視覺上，我需要去從starting point到end point。

謝謝！

Answer 1

這是我的解決方案。您可以使用.loc函數，該函數將索引作爲第一個參數，將列名作爲第二個參數。

更多here

import pandas as pd 
import numpy as np 

employees = [0, 0, 0, 1, 0, 0, 0, 0, 0, 0] 
levels = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] 
df = pd.DataFrame({"Employees":employees, "Level":levels}) 

#substitution logic 
temp = df['Employees'][3] 
df.loc[3, 'Employees'] = '' 
df.loc[1, 'Employees'] = temp 
#print output 
print df 

OUTPUT：

Employees Level 
0   0  1 
1   1  2 
2   0  3 
3    4 
4   0  5 
5   0  6 
6   0  7 
7   0  8 
8   0  9 
9   0  10 

Answer 2

用途：

df = pd.DataFrame({"Employees":['','','','empployee_object','','','','','',''], 
        "Level":range(1,11)}, index=range(1,11)) 
print (df) 
      Employees Level 
1       1 
2       2 
3       3 
4 empployee_object  4 
5       5 
6       6 
7       7 
8       8 
9       9 
10      10 

#move value from 4 index to 2 index in Employees column 
df.loc[2, 'Employees'] = df.loc[4, 'Employees'] 
#set empty string to original 
df.loc[4, 'Employees'] = '' 
print (df) 
      Employees Level 
1       1 
2 empployee_object  2 
3       3 
4       4 
5       5 
6       6 
7       7 
8       8 
9       9 
10      10