我不認爲這有問題,但是有沒有辦法將多層次,不均勻結構的列表信息合併爲一個「長」格式的數據幀?將不均勻的分層列表轉換爲數據幀
具體來說:
library(XML)
library(plyr)
xml.inning <- "http://gd2.mlb.com/components/game/mlb/year_2009/month_05/day_02/gid_2009_05_02_chamlb_texmlb_1/inning/inning_5.xml"
xml.parse <- xmlInternalTreeParse(xml.inning)
xml.list <- xmlToList(xml.parse)
## $top$atbat
## $top$atbat$pitch
## des id type x y
## "Ball" "310" "B" "70.39" "125.20"
凡下面是結構:
> llply(xml.list, function(x) llply(x, function(x) table(names(x))))
$top
$top$atbat
.attrs pitch
1 4
$top$atbat
.attrs pitch
1 4
$top$atbat
.attrs pitch
1 5
$bottom
$bottom$action
b des event o pitch player s
1 1 1 1 1 1 1
$bottom$atbat
.attrs pitch
1 5
$bottom$atbat
.attrs pitch
1 5
$bottom$atbat
.attrs pitch runner
1 5 1
$bottom$atbat
.attrs pitch runner
1 7 1
$.attrs
$.attrs$num
character(0)
$.attrs$away_team
character(0)
$.attrs$
我想是有從命名矢量從間距類別的數據幀,沿着(top,atbat,bottom)。因此,由於列數不同,我需要忽略不適合data.frame的級別。事情是這樣的:
first second third des x
1 top atbat pitch Ball 70.29
2 top atbat pitch Strike 69.24
3 bottom atbat pitch Out 67.22
是否有這樣做的一個優雅的方式?謝謝!
相關問題:http://stackoverflow.com/questions/2067098/how-to-transform-xml-data-into-a-data-frame – apeescape 2010-08-05 19:00:31