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所以我正在做一個俄羅斯方塊遊戲作爲一個學校項目在C.我遇到了一個小問題,以下情況。 在俄羅斯方塊當一個完成一個水平行時,該行應該被刪除,並且該行上的所有東西都應該向下移動一個地方。關於我的代碼的奇怪之處在於,當我將一個塊放在板的左側或中央時,塊呆在那裏就像它應該。但是,當我在板子的右側放置一個塊時,它會立即被刪除。 我把我的源代碼放在下面,所以你可以看到我在說什麼。C俄羅斯方塊,地方塊
功能checkfory(INT ycheckup,詮釋YP)
if(ycheckup==1)
{
yp++;
return yp;
}
else if(ycheckup==0)
{
yp=0;
return yp;
}
主營:
int Block_O[2][2] = {{1,1},{1,1}};
int printb[8][4] = {{0,0,0,0},{0,0,0,0},{0,0,0,0},{0,0,0,0},{0,0,0,0},{0,0,0,0},{0,0,0,0},{0,0,0,0},{0,0,0,0}};
int saveb[8][4] = {{0,0,0,0},{0,0,0,0},{0,0,0,0},{0,0,0,0},{0,0,0,0},{0,0,0,0},{0,0,0,0},{0,0,0,0},{0,0,0,0}};
int x;
int y;
int i;
int xp = 0;
int yp = 0;
int ycheckup = 0;
int ch1;
int ch2;
int ytemp;
int ycheck = 0;
int xcheck = 2;
while(1)
{
for(y=0;y<8;y++)
{
for(x=0;x<4;x++)
{
if(y==ycheck && x==xcheck || y==ycheck+1 && x==xcheck || y==ycheck && x==xcheck+1 || y==ycheck+1 && x==xcheck+1)//Looks for place to put block in
{
//printf(" %d ",xp);
printb[y][x] = Block_O[yp][xp];
printf("%d", printb[y][x]);
ycheckup=1;
xp++;
}
else
{
printb[y][x] = saveb[y][x];
printf("%d", printb[y][x]);
ycheckup=0;
}
}
//checkycor(ycheck,printb);
yp = checkfory(ycheckup, yp);
xp=0;
printf("\n");
}
for(i=0; i<30000000; i++) //Delay
{
;
}
ycheck++;
system("cls");
if(ycheck==7 || printb[ycheck+1][xcheck] == 1 || printb[ycheck+1][xcheck+1] == 1) //Checks for correlation
{
for(y=0;y<8;y++)
{
for(x=0;x<4;x++)
{
saveb[y][x] = printb[y][x];
if((printb[y][x] == 1) && (printb[y][x+1] == 1) && (printb[y][x+2] == 1) && (printb[y][x+3] == 1)) //Checks for full row
{
ytemp = y;
for(y=ytemp;y>0;y--)
{
for(x=0;x<4;x++)
{
if(y>0)
{
saveb[y][x] = printb[y-1][x]; //moves everything above deleted row, one row down
}
else
{
saveb[y][x] = 0;
}
printb[y][x] = saveb[y][x];
}
}
}
}
}
ycheck=0;
}
if (kbhit()!=0)
{
ch1 = getch();
ch2 = 0;
ch2 = getch();
switch(ch2)
{
case 75:
xcheck--;
break; //left
case 77:
xcheck++;
break;
default:
;
break;
};
}
}
我解決了這個問題,謝謝你的幫助! 我想我可能會展示一切,以防有些人想要測試它。 – user3177617