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我是新來的數組主題和在這種情況下使用for循環，所以我希望有人可以給我指示如何解決這個問題。Python：如何比較列表與二維數組列表？
我有一個列表的列表，看起來像這樣：
[[1, 0, 0], [0, 1, 0], [1, 1, 0], [0, 0, 1], [1, 0, 1], [0, 1, 1], [1, 1, 1]]
和一個二維數組，它看起來像這樣：
[[1 0 0]
[1 0 1]
[1 1 1]
[1 0 0]
[1 1 0]
[1 0 1]
[1 1 1]
[0 0 1]
[0 0 1]]
數組最終將有接近420K的記錄，我會就像我可以看清清單中列出的組合的次數。我試圖用一個for循環，像這樣：
from matplotlib import pyplot as plt
import numpy as np
from matplotlib_venn import venn3, venn3_circles
import os
import sys
from itertools import islice
input_file= "/home/ruchik/bodyMap_Data/bodyMap_Files/final.txt";
col0_idx = 6
col1_idx = 1
col2_idx = 2
print "number of sys arg", len(sys.argv)
print "sys arg list", sys.argv
input_file = sys.argv[1]
col1_idx = int(sys.argv[2])
col2_idx = int(sys.argv[3])
## keep it real ;)
col1_idx -= 1
col2_idx -= 1
print >> sys.stderr,'File is {file} and used columns are {col1} and {col2}.'.format(file=input_file, col1=col0_idx+col1_idx+1, col2=col2_idx+col0_idx+1)
## Openning and reading the file
#f = open(input_file, "r")
#g = open("final_fixed.txt", "w")
#print "Opened File Handle", f
#
#for line in f:
# if line.strip():
# g.write("\t".join(line.split()[7:]) + "\n")
#f.close()
#g.close()
#print "File created."
#f = open("final_fixed.txt", "r")
f = open(input_file, "r")
# header_all is a list of the content of the 1st line from position col0_idx-th to last-column-th
header_all_list = []
header_all_list = f.readline().rstrip("\n").split('\t')[col0_idx:]
header_reduced = [header_all_list[col1_idx], header_all_list[col2_idx], 'others']
# data_all is a (line-wise) list of (column-wise) list
# with the content of each line but the 1st one from position col0_idx-th to last-column-th
data_all_lol = []
for line in f:
data_all_lol.append(line.rstrip("\n").split('\t')[col0_idx:])
# just print the data_all list of list ... to make sure it is all fine up to there
#for i in range(len(data_all)):
# for j in range(len(data_all[i])):
# print >> sys.stderr, 'all data {col_i} , {col_j} : {val_ij}'.format(col_i=i+1, col_j=j+1+col0_idx, val_ij = data_all[i][j])
op_lol = [[1, 0, 0], [0, 1, 0], [1, 1, 0], [0, 0, 1], [1, 0, 1], [0, 1, 1], [1, 1, 1]]
count = [0, ] * len(op_lol)
for i in range(len(op_lol)):
for j in range(len(data_reduced_transposed_npa)):
if list(data_reduced_transposed_npa[j]) == op_lol[i]:
count[i] += 1
op = [[1, 0, 0], [0, 1, 0], [1, 1, 0], [0, 0, 1], [1, 0, 1], [0, 1, 1], [1, 1, 1]]
count2 = [0, ] * len(op_lol)
for column in data_reduced_npa:
for j in range(len(op_lol)):
count2[j] += 1
#for k in range(len(op)):
# print str(op[k]) + ': ' + str(count[k])
#header_venn3 = header_venn
#data_venn3 = data_venn
#print >> sys.stderr,"\nvenn3 order :"
#print >> sys.stderr,"(Abc, aBc, ABc, abC, AbC, aBC, ABC)"
#print >> sys.stderr,"venn3 header :"
#print >> sys.stderr, header_venn3
#print >> sys.stderr,"venn3 data :"
#for i in range(len(data_venn3)):
# for j in range(len(data_venn3[i])):
# print >> sys.stderr, 'venn3 data {col_i} , {col_j} : {val_ij}'.format(col_i=i, col_j=j, val_ij = data_venn3[i][j])
## Making the venn'
plt.figure(figsize=(4,4))
v = venn3(subsets=count, set_labels = ('Introns', 'Heart', 'Others'))
v.get_patch_by_id('100').set_alpha(1.0)
v.get_patch_by_id('100').set_color('white')
v.get_label_by_id('100').set_text('Unknown')
plt.show()
但這只是調換二維數組並打印，對於我來說，我究竟做錯了什麼？
我不知道我理解的2D名單和二維數組 – alfasin