I. XSLT 1.0解:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:variable name="vStyle" select="document('')"/>
<xsl:template match="myString">
<xsl:variable name="vStr" select="."/>
<root>
<myCharacters>
<xsl:for-each select=
"($vStyle//node()|$vStyle//@*|$vStyle//namespace::*)
[not(position() > string-length($vStr))]">
<character>
<id><xsl:value-of select="position()"/></id>
<value><xsl:value-of select="substring($vStr,position(),1)"/></value>
</character>
</xsl:for-each>
</myCharacters>
</root>
</xsl:template>
</xsl:stylesheet>
當這個變換所提供的XML文檔應用:
<root>
<myString>ABBCD</myString>
</root>
有用,正確的結果產生:
<root>
<myCharacters>
<character>
<id>1</id>
<value>A</value>
</character>
<character>
<id>2</id>
<value>B</value>
</character>
<character>
<id>3</id>
<value>B</value>
</character>
<character>
<id>4</id>
<value>C</value>
</character>
<character>
<id>5</id>
<value>D</value>
</character>
</myCharacters>
</root>
可替代地,與FXSL一個可以使用str-map
模板這樣的:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:testmap="testmap" xmlns:f="http://fxsl.sf.net/"
xmlns:ext="http://exslt.org/common" exclude-result-prefixes="xsl f ext testmap">
<xsl:import href="str-dvc-map.xsl"/>
<testmap:testmap/>
<xsl:variable name="vTestMap" select="document('')/*/testmap:*[1]"/>
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="myString">
<xsl:variable name="vrtfChars">
<xsl:call-template name="str-map">
<xsl:with-param name="pFun" select="$vTestMap"/>
<xsl:with-param name="pStr" select="."/>
</xsl:call-template>
</xsl:variable>
<myCharacters>
<xsl:apply-templates select="ext:node-set($vrtfChars)/*"/>
</myCharacters>
</xsl:template>
<xsl:template name="enumChars" match="*[namespace-uri() = 'testmap']"
mode="f:FXSL">
<xsl:param name="arg1"/>
<character>
<value><xsl:value-of select="$arg1"/></value>
</character>
</xsl:template>
<xsl:template match="character">
<character>
<id><xsl:value-of select="position()"/></id>
<xsl:copy-of select="*"/>
</character>
</xsl:template>
</xsl:stylesheet>
以產生相同的正確的結果 :
<myCharacters>
<character>
<id>1</id>
<value>A</value>
</character>
<character>
<id>2</id>
<value>B</value>
</character>
<character>
<id>3</id>
<value>B</value>
</character>
<character>
<id>4</id>
<value>C</value>
</character>
<character>
<id>5</id>
<value>D</value>
</character>
</myCharacters>
二, XSLT 2.0解決方案 - 比其他的答案更短,更簡單:
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="myString">
<root>
<myCharacters>
<xsl:for-each select="string-to-codepoints(.)">
<character>
<id><xsl:value-of select="position()"/></id>
<value><xsl:value-of select="codepoints-to-string(.)"/></value>
</character>
</xsl:for-each>
</myCharacters>
</root>
</xsl:template>
</xsl:stylesheet>
當在同一個XML文檔(以上)應用時產生想要的,正確的結果:
<root>
<myCharacters>
<character>
<id>1</id>
<value>A</value>
</character>
<character>
<id>2</id>
<value>B</value>
</character>
<character>
<id>3</id>
<value>B</value>
</character>
<character>
<id>4</id>
<value>C</value>
</character>
<character>
<id>5</id>
<value>D</value>
</character>
</myCharacters>
</root>
一個簡單的方法將做一個VBscript函數調用inb你的xslt,它將取值並返回一組節點。 – PSL 2013-03-17 18:30:38