SQL原料到MySQL查詢

Question

我需要執行下面的查詢：

select Clients.Zip, AVG(SpentT) as Average_Spent_Per_Zipcode 
from 
    (select CLIENT.CLIENT_ID AS ClientID, Averages.Spent AS SpentT, CLIENT.ZIPCODE AS Zip 
    from CLIENT, 
     (select CLIENT_ID, AVG(MENU.PRICE) AS Spent 
     from ORDER_HISTORY, MENU 
     where (ORDER_HISTORY.FOOD = MENU.FOOD) 
     AND (ORDER_HISTORY.RESTAURANT_ID = MENU.RESTAURANT_ID) 
     group by ORDER_HISTORY.CLIENT_ID) 
     AS Averages 
    where CLIENT.CLIENT_ID = Averages.CLIENT_ID) AS Clients 
group by Clients.Zip 
order by Average_Spent_Per_Zipcode DESC 

我知道這可能不是最簡單的查詢，但這個想法是找到在餐廳上花費最多的郵編平均。

我已經試過

sqlP1=text('select Clients.Zip, AVG(SpentT) as Average_Spent_Per_Zipcode from (select CLIENT.CLIENT_ID AS ClientID, Averages.Spent AS SpentT, CLIENT.ZIPCODE AS Zip from CLIENT, (select CLIENT_ID, AVG(MENU.PRICE) AS Spent from ORDER_HISTORY, MENU where (ORDER_HISTORY.FOOD = MENU.FOOD) AND (ORDER_HISTORY.RESTAURANT_ID = MENU.RESTAURANT_ID) group by ORDER_HISTORY.CLIENT_ID) AS Averages where CLIENT.CLIENT_ID = Averages.CLIENT_ID) AS Clients group by Clients.Zip order by Average_Spent_Per_Zipcode DESC') 
result= db.engine.execute(sql) 

，但我不斷收到任何錯誤，我是新來這個，所以我不知道如果日誌將有助於/其中id找到他們。
如果有人知道如何執行這個查詢，那就太棒了！ 您的幫助非常感謝！

Answer 1

試試這個：

SELECT C.ZIPCODE, AVG(M.PRICE) AS Average_Spent_Per_Zipcode 
FROM ORDER_HISTORY OH 
INNER JOIN MENU M ON OH.FOOD = M.FOOD AND OH.RESTAURANT_ID = M.RESTAURANT_ID 
INNER JOIN CLIENT C ON OH.CLIENT_ID = C.CLIENT_ID 
GROUP BY C.ZIPCODE 
ORDER BY AVG(M.PRICE) DESC;