SQL存儲過程逃亡二選擇並返回一個值

Question

我怎麼會去修改存儲過程運行兩個SQL語句

CREATE procedure [dbo].[hms_GetEmployeeSalaryRecordsByContractId] 
(
@Id int 
) 
as 
SELECT c.* 
FROM contract c 
where c.emp_no = @Id AND c.leave_date='1900-01-01 00:00:00.000' and c.main_contract=1 

select * from salary s where s.contract_id = firstquery.contract_id 

基於合同

如果多一個以上可以找到兩個工資記錄找到工資後，我需要做一個sum(s.salary)，然後在存儲過程中將其作爲十進制值返回。

我已經這樣做了，到目前爲止現在

USE [pamsv83x] 
GO 
/****** Object: StoredProcedure [dbo].[hms_GetEmployeeSalaryRecordsByContractId] Script Date: 08/29/2013 10:45:05 ******/ 
SET ANSI_NULLS ON 
GO 
SET QUOTED_IDENTIFIER ON 
GO 

Create procedure [dbo].[hms_GetEmployeeSalaryRecordsByContractEmpNo] 
(
@Id int, 
@sallaryresult decimal(8,2) OUTPUT 
) 
as 
DECLARE @contract_id int 
DECLARE @totalsallary decimal(8,2) 
set @contract_id=(SELECT c.contract_id 
FROM contract c 
where c.emp_no = @Id AND c.leave_date='1900-01-01 00:00:00.000' and c.main_contract=1) 


SELECT *,SUM(salary) 
from salary s 
where s.emp_no=@contract_id 
return 

修改2 ----- 他們可以有multple合約，但可以有multple sallarys

Create procedure [dbo].[hms_GetEmployeeSalaryRecordsByContractEmpNo] 
(
@Id int, 
@sallaryresult decimal(8,2) OUTPUT 
) 
as 
DECLARE @contract_id int 
DECLARE @totalsallary decimal(8,2) 
set @contract_id=(SELECT c.contract_id 
FROM contract c 
where c.emp_no = @Id AND c.leave_date='1900-01-01 00:00:00.000') 


SELECT *,SUM(salary + old_salary) 
from salary s 
where s.contract_id=@contract_id 
return 

Answer 1

聯接工資聯繫會做這個更好。喜歡的東西：

CREATE procedure [dbo].[hms_GetEmployeeSalaryRecordsByContractId] 
(
@Id int 
) 
as 
SELECT 
    c.contract_id 
    ,SUM(s.salary + s.old_salary)  
FROM 
    contract c 
INNER JOIN 
    salary s 
    ON c.contract_id = s.contract_id  
WHERE 
     c.emp_no = @Id 
    AND c.leave_date = '1900-01-01 00:00:00.000' 
    AND c.main_contract = 1 

GROUP BY 
    c.contract_id 

以上將接受僱員ID和CONTACT_ID返回聚合薪水值。