如何獲得二進制格式的SQL JOIN輸出

患者就診表

Visit ID Patient ID Date Disease ID 
    101   1  22-Feb  11 
    102   5  5-Apr  22 
    103   3  2-Jul  77 
    104   2  4-Feb  55 
    105   6  5-Jan  99 
    106   2  6-Jan  66 
    107   2  8-Jan  77 
    108   7  9-Jan  44 
    109   5  22-Jan  88 
    110   1  23-Jan  33

和第2表，

疾病表

Disease ID Disease Name 

     11 Asthama 
     22 TB 
     33 Flu 
     44 AIDS 
     55 Cancer 
     66 Heart Disease 
     77 ABC 
     88 XYZ 
     99 MNO

我需要的輸出如下：病人標識符爲Row和Disease爲列的表格，Th e二進制值指示哪個患者患有哪種疾病。

我應該使用什麼查詢？

The table with Patient ID as Row and Disease as columns, The binary values indicating which patient has which disease

來源

2017-03-02 Ankit Chaudhari

這是用於SQL Server或MySQL？你在這個問題上都有兩個標籤。 –

搜索PIVOT。對此有很多答案。 – DVT

這被稱爲數據透視表，你可以在SO上找到mysql和sql server的答案。 – Shadow

如果您正在使用SQL Server試試這個，希望能幫助。使用Case Expression

select t1.patient_id, 
    case when t2.disease_name='Asthma' then 1 else 0 end as Asthma, 
    case when t2.disease_name='TB' then 1 else 0 end as TB, 
    case when t2.disease_name='Flu' then 1 else 0 end as Flu, 
    case when t2.disease_name='AIDS' then 1 else 0 end as AIDS, 
    case when t2.disease_name='Cancer' then 1 else 0 end as Cancer, 
    case when t2.disease_name='Heart Disease' then 1 else 0 end as 'Heart Disease', 
    case when t2.disease_name='ABC' then 1 else 0 end as ABC, 
    case when t2.disease_name='XYZ' then 1 else 0 end as XYZ, 
    case when t2.disease_name='MNO' then 1 else 0 end as MNO 
from #table1 t1 
left join #table2 t2 
on t1.Disease_id=t2.Disease_id 
order by t1.patient_id

來源

2017-03-02 02:21:36

試試這個

SELECT PatientID, [Asthama],[TB],[Flu],[AIDS],[Cancer],[Heart Disease], [ABC],[XYZ],[MNO] 
FROM 
(SELECT P.PatientID,D.Disease from Patient P inner join Disease D on  P.DiseaseID=D.DiseaseID) AS SourceTable 
PIVOT 
(
count(Disease) 
FOR Disease IN ([Asthama],[TB],[Flu],[AIDS],[Cancer],[Heart Disease],[ABC],[XYZ],[MNO]) 
) AS PivotTable;

來源

2017-03-02 04:34:04

如何獲得二進制格式的SQL JOIN輸出

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