如何獲得運行在SQL Server

Question

您好我有從表票據與名稱數量一列一列的總和 我想，顯示數量列這樣的運行總和列：

Qty Run_Sum 
1  1 
2  3 
3  6 
4  10 
5  15 

建議我一些適當的方法，使運行某些thankx

Answer 1

如果RDBMS支持窗口功能，

爲SQL Server 2012

SELECT Qty, 
     SUM(Qty) OVER (ORDER BY Qty) AS CumulativeTOTAL 
FROM tableName 

• SQLFiddle Demo

爲SQL Server 2008

SELECT a.Qty, (SELECT SUM(b.Qty) 
       FROM TableName b 
       WHERE b.Qty <= a.Qty) 
FROM TableName a 
ORDER BY a.Qty; 

• SQLFiddle Demo

Answer 2

下面是使用Oracle /分析函數的示例：

select id, qty, sum(qty) over(order by id asc) run_sum 
from test; 

http://www.sqlfiddle.com/#!4/3d149/1

Answer 3

SQLFiddle demo

SELECT Qty, 
SUM(Qty) OVER (ORDER BY Qty) Run_Sum 
FROM t ORDER BY Qty 

對於SQLServer的前2012：

select Qty, 
(select sum(Qty) from t where Qty<=t1.Qty) 
from t t1 order by Qty 

SQLFiddle demo

或者你也可以不用子查詢：

select t1.Qty, sum(t2.Qty) 
from t t1 
join t t2 on (t1.Qty>=t2.Qty) 
group by t1.Qty 
order by t1.Qty 

SQLFiddle demo

Answer 4

入住這

DECLARE @TEMP table 
(
    ID int IDENTITY(1,1), 
    QUANTITY int 
) 

INSERT INTO @TEMP 
SELECT 1 UNION ALL 
SELECT 2 UNION ALL 
SELECT 3 UNION ALL 
SELECT 4 UNION ALL 
SELECT 8 UNION ALL 
SELECT 7 UNION ALL 
SELECT 5 UNION ALL 
SELECT 1 

SELECT t.QUANTITY AS Qty, SUM(t1.QUANTITY) AS Run_Sum 
FROM @TEMP t 
INNER JOIN @TEMP t1 
ON t1.ID <= t.ID 
GROUP BY t.ID, t.QUANTITY 
ORDER BY t.ID 

Answer 5

;with cte as (
    select top 1 Qty, Qty as RunningSum 
    from Bills 
    order by Qty 

    union all 

    select t.Qty, cte.RunningSum + t.Qty 
    from cte 
    inner join Bills t on cte.Qty + 1 = t.Qty 
) 
select * from cte 

Answer 6

@mahmud： 看看這給

DECLARE @Bills table 
(
    QUANTITY int 
) 

INSERT INTO @Bills 
SELECT 2 UNION ALL 
SELECT 6 UNION ALL 
SELECT 7 UNION ALL 
SELECT 1 UNION ALL 
SELECT 3 UNION ALL 
SELECT -5 UNION ALL 
SELECT 5 UNION ALL 
select 1 

;with cte as (
    select top 1 QUANTITY, QUANTITY as RunningSum 
    from @Bills 
    order by QUANTITY 

    union all 

    select t.QUANTITY, cte.RunningSum + t.QUANTITY 
    from cte 
    inner join @Bills t on cte.QUANTITY + 1 = t.QUANTITY 
) 
select * from cte