SQL GROUP BY與濾波器SELECT

如果我有下面的示例數據：SQL GROUP BY與濾波器SELECT

╔══════════════╦══════════════════╦════════════╦═══════╗ 
║ Client ║  con_id  ║ mat1_07_03 ║ Ccode ║ 
╠══════════════╬══════════════════╬════════════╬═══════╣ 
║ Clients Name ║ C13109BBFD511534 ║ $1,062.00 ║ NOFL ║ 
║ Clients Name ║ C11AC9BBF74D6882 ║ $879.73 ║ NOFL ║ 
║ Clients Name ║ C12A69BBF1ACB578 ║ $2,790.29 ║ NOFA ║ 
║ Clients Name ║ C12A69BBF1ACB578 ║ $912.00 ║ NOFL ║ 
║ Clients Name ║ C6B0CA1A767C9744 ║ $2,180.11 ║ NOFL ║ 
║ Clients Name ║ C11AC9BBF74D6882 ║ $878.67 ║ NOFA ║ 
║ Clients Name ║ C13B79BBF4F1F450 ║ $300.00 ║ NOFL ║ 
║ Clients Name ║ C12A69BBF1ACB578 ║ $1,790.67 ║ NOFL ║ 
║ Clients Name ║ CA6869E2FE38A449 ║ $240.00 ║ NOFA ║ 
║ Clients Name ║ C46439FB0D847140 ║ $3,392.66 ║ NOFL ║ 
║ Clients Name ║ C12A69BBF1ACB578 ║ $1,791.73 ║ NOFA ║ 
║ Clients Name ║ C13B49BBF12ED236 ║ $0.00  ║ NOFL ║ 
║ Clients Name ║ C12A69BBF1ACB578 ║ $879.73 ║ NOFL ║ 
╚══════════════╩══════════════════╩════════════╩═══════╝

，並應用以下查詢：

SELECT 
    [Client]=MAX(m.Client) 
    ,[CaseCount]=COUNT(m.con_id) 
    ,[AmtInDispute]=CONVERT(char, SUM(Convert(money, m.mat1_07_03)), 101) 
FROM lntmu11.matter m 
GROUP BY m.con_id 
ORDER BY COUNT(m.Client) DESC

我怎樣才能進一步羣Ccode列，以獲得COUNT有多少行是 NOFA或NOFL

我所需的輸出將顯示爲：

╔══════════╦═══════════╦═══════════════╦═══════════════╦══════════════╗ 
║ Client ║ CaseCount ║ NOFACaseTotal ║ NOFLCaseTotal ║ AmtInDispute ║ 
╠══════════╬═══════════╬═══════════════╬═══════════════╬══════════════╣ 
║ Client A ║  3548 ║   2000 ║   1548 ║ 5,658,307.60 ║ 
║ Client B ║  3366 ║   100 ║   3266 ║ 2,885,649.48 ║ 
║ Client C ║  3014 ║   800 ║   2214 ║ 2,851,507.13 ║ 
║ Client D ║  2340 ║   340 ║   2000 ║ 3,467,207.12 ║ 
╚══════════╩═══════════╩═══════════════╩═══════════════╩══════════════╝

來源

2014-10-01 bumble_bee_tuna

+1爲了花時間格式化您的問題，所以很好。 – stakx 2014-10-01 19:46:24

只需使用條件彙總：

SELECT m.Client, CaseCount = COUNT(m.con_id), 
     CONVERT(varchar(255), SUM(Convert(money, m.mat1_07_03)), 101) as AmtInDispute 
     sum(case when cCode = 'NOFA' then 1 else 0 end) as NOFACaseTotal, 
     sum(case when cCode = 'NOFL' then 1 else 0 end) as NOFLCaseTotal, 
FROM lntmu11.matter m 
GROUP BY m.client 
ORDER BY COUNT(m.Client) DESC;

注意：做轉換爲字符時，總是包括長度（T-SQL）。

來源

2014-10-01 19:38:39

您可以使用條件聚合獲取其他2列。使用具有CASE表達式的聚合函數來計算每個列所需的Ccode值。

SELECT 
    [Client]=MAX(m.Client) 
    ,[CaseCount]=COUNT(m.con_id) 
    ,NOFACaseTotal = sum(case when m.Ccode = 'NOFA' then 1 else 0 end) 
    ,NOFLCaseTotal = sum(case when m.Ccode = 'NOFL' then 1 else 0 end) 
    ,[AmtInDispute]=CONVERT(char(50), SUM(Convert(money, m.mat1_07_03)), 101) 
FROM lntmu11.matter m 
GROUP BY m.con_id 
ORDER BY COUNT(m.Client) DESC;

請參閱SQL Fiddle with Demo。

來源

2014-10-01 19:38:17 Taryn

就像Gordon和Bluefeet所說的條件聚合FTW！

SELECT 
    [Client]=MAX(m.Client) 
    ,[CaseCount]=COUNT(m.con_id) 
    ,[AmtInDispute]=CONVERT(char, SUM(Convert(money, m.mat1_07_03)), 101) 
    ,[NOFACaseTotal]=sum(case when Ccode = 'NOFA' then 1 else 0 end) 
    ,[NOFLCaseTotal]=sum(case when Ccode = 'NOFL' then 1 else 0 end) 
FROM lntmu11.matter m 
GROUP BY m.con_id 
ORDER BY COUNT(m.Client) DESC

來源

2014-10-01 19:39:58 Donal

SQL GROUP BY與濾波器SELECT

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