爲什麼這個SQLAlchemy查詢返回不需要的邏輯值？

Question

posts_query = (db.session.query(Post). 
        join(PostOption,PostOption.post_id == post_obj.id). 
        filter(and_(PostOption.key == "name", 
           PostOption.val == 'a')). 
        filter(Post.place_id == post_obj.place_id) 
        ) 

    print map(lambda x:get_post_values(x),posts_query.all()) 

回報

[{u'name': u'a'}, {u'name': u'a'}, {u'name': u'a'}, {u'name': u'a'}, {u'name': u'a'}, {u'name': u'a'}, {u'name': u'a'}, {u'name': u'a'}, {u'name': u'a'}, {u'name': u'a'}, {u'name': u'a'}, {u'name': u'a'}, {u'name': u'a'}, {u'name': u'a'}, {u'name': u'b'}, {u'name': u'b'}, {u'name': u'b'}, {u'name': u'b'}, {u'name': u'b'}, {u'name': u'b'}, {u'name': u'b'}, {u'name': u'b'}, {u'name': u'b'}, {u'name': u'b'}, {u'name': u'b'}, {u'name': u'b'}, {u'name': u'b'}] 

Answer 1

認爲它的加入，看來你要加入後到PostOptions PostOption.post_id =一些文字值。認爲你的意思是這樣的：

posts_query = (db.session.query(Post). 
    join(PostOption, PostOption.post_id == Post.id). 
    filter(and_(PostOption.key == "name", PostOption.val == 'a')). 
    filter(Post.place_id == post_obj.place_id). 
    filter(Post.id == post_obj.id) 
) 

Answer 2

胡亂猜測這裏：

附上and_內place_id條款：

posts_query = (db.session.query(Post). 
      join(PostOption,PostOption.post_id == post_obj.id). 
      filter(and_(PostOption.key == "name", 
         PostOption.val == 'a', 
         Post.place_id == post_obj.place_id)) 
      )