當用戶使用用戶名和密碼登錄時獲取用戶ID

-1

我需要輸入USER表的USER_ID字段作爲另一個表中的外鍵。因此，我認爲我需要在用戶登錄時啓動一個會話。我很難讓它在任何地方回顯。我可以開始一個會話，允許我回顯USERNAME，但不能複製該ID。當用戶使用用戶名和密碼登錄時獲取用戶ID

請幫忙嗎？我的處理代碼如下。我也粘貼了我暫時試圖迴應測試的部分。

處理腳本：

<?php 
session_start(); 
$error_message = array(); 
$error = false; 
$dbhost  = "localhost"; 
$dbname  = "xxx"; 
$dbuser  = "xxx"; 
$dbpass  = "xxx"; 

$conn = new PDO("mysql:host=$dbhost;dbname=$dbname",$dbuser,$dbpass); 

$user = $_POST['uname']; 
$password = $_POST['pword']; 

if($user == '') { 
    $error_message[] = 'You have not entered the required username.'; 
    $error = true; 
} 
if($password == '') { 
    $error_message[] = 'You have not entered the required username'; 
    $error = true; 
} 

$result = $conn->prepare("SELECT * FROM USER WHERE USERNAME= :un AND PASSWORD= :pw"); 
$result->bindParam(':un', $user); 
$result->bindParam(':pw', $password); 
$result->execute(); 

while ($rows = $result->fetch(PDO::FETCH_NUM)) { 



if($rows > 0) { 

$_SESSION['Logged_In'] = true; 
$_SESSION['username'] = $user; 
$_SESSION['USER_ID'] = $rows['USER_ID']; 
header('Location: index.php'); 
} 

else{ 

    $error_message[] = 'Your username and password are not correct. Try again.'; 
    $error = true; 
} 

if($error) { 
    $_SESSION['ERROR_MESSAGE'] = $error_message; 
    session_write_close(); 
    header("location: log_in.php"); 
    exit(); 
}} 

?>

我想要的USER_ID出現：

<?php 
     session_start(); 
     if(isset($_SESSION['Logged_In'])) 
{ 
    echo '<br><br>'; 
    echo 'You are logged in as '; 
    echo $_SESSION['username']; 
    echo '<br>'; 
    echo "ID = ".$_SESSION['USER_ID']; 
    echo '<br>'; 
    echo '<a href="logout.php"> 
Click here to log out.</a>'; 
} 
else 
{ 
    echo '<br>'; 
    echo 'You are not logged in!<br>'; 
    echo '<a href="log_in.php">Click here to log in,</a><br>'; 
    echo '<a href="register.php">or click here to register.</a>'; 
} 
?>

來源

2014-01-13 user3183576

什麼是會議的問題呢？ –

您是否嘗試過使用FETCH_ASSOC而不是FETCH_NUM？ –

@LucaIaco完美無缺！非常感謝你:) :) – user3183576

使用FETCH_ASSOC代替FETCH_NUM

來源

2014-01-14 08:23:04

當用戶使用用戶名和密碼登錄時獲取用戶ID

回答

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