如何在Visual Studio中構建此代碼？

Question

請記住，這是我在這裏的第一個問題，我也是C＃的新手。

我將代碼從this YouTube video複製到Visual Studio，但它不會生成。我無法將項目添加到empList。

更新

我真的很感謝你的幫助，但它仍然沒有，儘管你的建議建設（例如我確實有使用System.Collections.Generic命名空間）。我甚至完全複製了Rion的代碼，但仍然無法構建。這些行有錯誤：

）預計「，」;預計

和

無效表達術語「」

List<Employee> empList = new List<Employee>(); 
empList.Add(new Employee() {ID = 101, Name = "Mary", Salary = 5000, Experience = 5}); 
empList.Add(new Employee() {ID = 102, Name = "Maria", Salary = 6000, Experience = 2}); 
empList.Add(new Employee() {ID = 106, Name = "Mike", Salary = 4000, Experience = 4}); 
empList.Add(new Employee() {ID = 104, Name = "John", Salary = 5000, Experience = 7}); 
Employee.PromoteEmployee(empList); 

它不完全一樣在視頻中的代碼，因爲我還是改了一點，但它不會建立。

class Program 
{ 
    public static void Main(string[] args) 
    { 
     List<Employee> empList = new List<Employee>(); 


     empList.Add(new Employee() {ID = 101, Name = "Mary", Salary = 5000, Experience = 5}); 
     empList.Add(new Employee() {ID = 102, Name = "Maria", Salary = 6000, Experience = 2}); 
     empList.Add(new Employee() {ID = 106, Name = "Mike", Salary = 4000, Experience = 4}); 
     empList.Add(new Employee() {ID = 104, Name = "John", Salary = 5000, Experience = 7}); 

     Employee.PromoteEmployee(empList); 
    } 


} 

class Employee 
{ 
    public int ID; 
    public string Name; 
    public int Salary; 
    public int Experience; 

    public static void PromoteEmployee(List<Employee> employeeList) 
    { 
     foreach (Employee employee in employeeList) 
     { 
      if(employee.Experience >=5) 
      { 
       Console.WriteLine(employee.Name + " promoted"); 
       Console.ReadLine(); 
      } 
     } 
    } 
} 

Answer 1

將項目

如果您需要任何項目添加到列表中，您考慮加入另一行：如果你想通過編程方式處理這個

empList.Add(new Employee() {ID = 42, Name = "Foo", Salary = 42, Experience = 0}); 

控制檯，您可以考慮請求用戶需要的每個值，構建一個Employee對象並將其存儲在您的empList：

// Building a new employee 
var newEmployee = new Employee(); 
// Request the ID 
Console.WriteLine("What is the Employee's ID?"); 
newEmployee.ID = Int32.Parse(Console.ReadLine()); 
// Request the Name 
Console.WriteLine("What is the Employee's Name?"); 
newEmployee.Name = Console.ReadLine(); 
// Continue for other properties here 

// After you have what you need, simply add it to the list 
empList.Add(newEmployee); 

檢查參考

既然你沒有明確張貼您可能使用的任何引用的命名空間，確保您使用的語句，才能正常使用List集合以下幾點：

using System.Collections.Generic; 

可能等待輸入

假設如果要輸出每個匹配的員工，那麼它應該是work as expected，但是代碼中的Console.ReadLine()可能等待用戶輸入，而不是完成遍歷對象的迭代。

嘗試將其放置您foreach循環之外的Employee.PromoteEmployee方法中：

public static void PromoteEmployee(List<Employee> employeeList) 
{ 
    foreach (Employee employee in employeeList) 
    { 
     if(employee.Experience >=5) 
     { 
      Console.WriteLine(employee.Name + " promoted"); 
     } 
    } 
    Console.ReadLine(); 
} 

例

你可以see a complete working example here，上面的例子中的輸出和低於適用代碼：

using System; 
using System.Collections.Generic; 

public class Program 
{ 
    public static void Main() 
    { 
     List<Employee> empList = new List<Employee>(); 
     empList.Add(new Employee() {ID = 101, Name = "Mary", Salary = 5000, Experience = 5}); 
     empList.Add(new Employee() {ID = 102, Name = "Maria", Salary = 6000, Experience = 2}); 
     empList.Add(new Employee() {ID = 106, Name = "Mike", Salary = 4000, Experience = 4}); 
     empList.Add(new Employee() {ID = 104, Name = "John", Salary = 5000, Experience = 7}); 

     Employee.PromoteEmployee(empList); 
    } 
} 

class Employee 
{ 
    public int ID; 
    public string Name; 
    public int Salary; 
    public int Experience; 

    public static void PromoteEmployee(List<Employee> employeeList) 
    { 
     foreach (Employee employee in employeeList) 
     { 
      if(employee.Experience >=5) 
      { 
       Console.WriteLine(employee.Name + " promoted"); 

      } 
     } 
     Console.ReadLine(); 
    } 
}