我正在尋找一種解決方法,在Lambert投影中將x和y軸刻度和標籤添加到Cartopy貼圖。Cartopy:軸標籤 - 解決方法
我提出的解決方案只是一種近似方法,它會對較大的地圖產生較差的結果:它涉及使用transform_points方法轉換所需的刻度位置以映射投影。爲此,我使用我的y軸(或x軸)的中值經度(或緯度)以及所需的緯度(或經度)滴答位置來計算地圖投影座標。見下面的代碼。因此,我假設沿着y軸(緯度沿着x軸)的恆定經度,這是不正確的,因此導致偏差。 (請注意所附數字中的差異:set_extent中設置的46°和最終的tick位置)。
有沒有更準確的解決方案呢? 任何提示,我可以如何處理這個問題,否則?
感謝您的任何意見!
import matplotlib.pyplot as plt
import cartopy.crs as ccrs
import numpy as np
def main():
#my desired Lambert projection:
myproj = ccrs.LambertConformal(central_longitude=13.3333, central_latitude=47.5,
false_easting=400000, false_northing=400000,
secant_latitudes=(46, 49))
arat = 1.1 #just some factor for the aspect ratio
fig_len = 12
fig_hig = fig_len/arat
fig = plt.figure(figsize=(fig_len,fig_hig), frameon=True)
ax = fig.add_axes([0.08,0.05,0.8,0.94], projection = myproj)
ax.set_extent([10,16,46,49])
#This is what is not (yet) working in Cartopy due to Lambert projection:
#ax.gridlines(draw_labels=True) #TypeError: Cannot label gridlines on a LambertConformal plot. Only PlateCarree and Mercator plots are currently supported.
x_lons = [12,13,14] #want these longitudes as tick positions
y_lats = [46, 47, 48, 49] #want these latitudes as tick positions
tick_fs = 16
#my workaround functions:
cartopy_xlabel(ax,x_lons,myproj,tick_fs)
cartopy_ylabel(ax,y_lats,myproj,tick_fs)
plt.show()
plt.close()
def cartopy_xlabel(ax,x_lons,myproj,tick_fs):
#transform the corner points of my map to lat/lon
xy_bounds = ax.get_extent()
ll_lonlat = ccrs.Geodetic().transform_point(xy_bounds[0],xy_bounds[2], myproj)
lr_lonlat = ccrs.Geodetic().transform_point(xy_bounds[1],xy_bounds[2], myproj)
#take the median value as my fixed latitude for the x-axis
l_lat_median = np.median([ll_lonlat[1],lr_lonlat[1]]) #use this lat for transform on lower x-axis
x_lats_helper = np.ones_like(x_lons)*l_lat_median
x_lons = np.asarray(x_lons)
x_lats_helper = np.asarray(x_lats_helper)
x_lons_xy = myproj.transform_points(ccrs.Geodetic(), x_lons,x_lats_helper)
x_lons_xy = list(x_lons_xy[:,0]) #only lon pos in xy are of interest
x_lons = list(x_lons)
x_lons_labels =[]
for j in xrange(len(x_lons)):
if x_lons[j]>0:
ew=r'$^\circ$E'
else:
ew=r'$^\circ$W'
x_lons_labels.append(str(x_lons[j])+ew)
ax.set_xticks(x_lons_xy)
ax.set_xticklabels(x_lons_labels,fontsize=tick_fs)
def cartopy_ylabel(ax,y_lats,myproj,tick_fs):
xy_bounds = ax.get_extent()
ll_lonlat = ccrs.Geodetic().transform_point(xy_bounds[0],xy_bounds[2], myproj)
ul_lonlat = ccrs.Geodetic().transform_point(xy_bounds[0],xy_bounds[3], myproj)
l_lon_median = np.median([ll_lonlat[0],ul_lonlat[0]]) #use this lon for transform on left y-axis
y_lons_helper = np.ones_like(y_lats)*l_lon_median
y_lats = np.asarray(y_lats)
y_lats_xy = myproj.transform_points(ccrs.Geodetic(), y_lons_helper, y_lats)
y_lats_xy = list(y_lats_xy[:,1]) #only lat pos in xy are of interest
y_lats = list(y_lats)
y_lats_labels =[]
for j in xrange(len(y_lats)):
if y_lats[j]>0:
ew=r'$^\circ$N'
else:
ew=r'$^\circ$S'
y_lats_labels.append(str(y_lats[j])+ew)
ax.set_yticks(y_lats_xy)
ax.set_yticklabels(y_lats_labels,fontsize=tick_fs)
if __name__ == '__main__': main()
感謝您的這種做法!網格線看起來有些扭曲,但放置蜱的功能工作得很好! – user3497890