測試數據
DECLARE @Table TABLE(trm_desc VARCHAR(300))
INSERT INTO @Table VALUES
('Supply: All goods supplied bla bla...'),
('Payment: to be made 10 April 2013'),
('Delivery: Today 07 March 2013'),
('Taxes: The price is bla bla...'),
('Others: other bla bla')
查詢
SELECT * FROM
(
SELECT LEFT(trm_desc, CHARINDEX(':', trm_desc)-1) AS Cols
,RIGHT(trm_desc, LEN(trm_desc)-CHARINDEX(':', trm_desc)-1) Value
FROM @Table) Q
PIVOT (MAX(Value)
FOR Cols
IN ([Supply],[Payment],[Delivery],[Taxes],[Others])
)p
結果集
╔═══════════════════════════════╦══════════════════════════╦═════════════════════╦═════════════════════════╦═══════════════╗
║ Supply ║ Payment ║ Delivery ║ Taxes ║ Others ║
╠═══════════════════════════════╬══════════════════════════╬═════════════════════╬═════════════════════════╬═══════════════╣
║ All goods supplied bla bla... ║ to be made 10 April 2013 ║ Today 07 March 2013 ║ The price is bla bla... ║ other bla bla ║
╚═══════════════════════════════╩══════════════════════════╩═════════════════════╩═════════════════════════╩═══════════════╝
[這裏有一個很好的資源,讓您開始。(HTTP://technet.microsoft.com/en-us/library/ms177410(v=sql.105).aspx) – Kermit
擡頭看看PIVOT併發帖讓你陷入困境 – Randy
這個問題看起來是題外話題,因爲OP正在尋找資源如何解決他們的問題。 – Kermit