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嗨!旋轉矩形並將其移動到正弦波 - 幫助使用graphics2D
我有下面的代碼使用以前的Stackoverflow的職位。
我想只是旋轉矩形的某個角度,並使其在正弦波中移動。
該代碼也旋轉整個正弦波。
我明白爲什麼會發生,但我不知道如何達到我的目的。
請幫忙!!!
非常感謝您抽出時間。
import java.awt.BorderLayout;
import java.awt.Color;
import java.awt.Dimension;
import java.awt.Graphics;
import java.awt.Graphics2D;
import java.awt.geom.AffineTransform;
import java.util.Timer;
import java.util.TimerTask;
import javax.swing.JFrame;
import javax.swing.JPanel;
public class Withrotation {
public static int i = 1;
public static Ticker t;
public static Repainter r;
public static int newx, newy;
public static void main(String[] args) {
final JFrame frame = new JFrame("Wavy!");
final WavyPanel wp = new WavyPanel();
frame.getContentPane().add(wp, BorderLayout.CENTER);
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
t = new Ticker(wp);
r = new Repainter(wp);
frame.pack();
frame.setVisible(true);
final Timer tickTimer = new Timer();
final Timer paintTimer = new Timer();
paintTimer.schedule(r, 1000, 50);
tickTimer.schedule(t, 1000, 10);
}
private static class WavyPanel extends JPanel {
private final Dimension size = new Dimension(640, 480);
private int amplitude = 50;
private int frequency = 5;
private double x1 = 0;
private double y1 = 500;
private int yBase = 0;
WavyPanel() {
super(true);
}
@Override
protected void paintComponent(final Graphics g) {
final Graphics2D g2 = (Graphics2D) g;
AffineTransform old = g2.getTransform();
g2.rotate(Math.toRadians(-30));
g2.clearRect(0, 0, this.getSize().width, this.getSize().height);
g2.setColor(Color.BLACK);
g2.fillRect((int) x1, (int) y1, 20, 80);
g2.setTransform(old);
}
@Override
public Dimension getPreferredSize() {
return size;
}
@Override
public Dimension getMinimumSize() {
return size;
}
@Override
public Dimension getMaximumSize() {
return size;
}
public void tick() {
x1 = x1 + 1;
final int waveLength = size.width/frequency;
yBase = (++yBase) % waveLength;
final double normalized = (double) yBase/(double) waveLength;
final double radians = normalized * Math.PI * 2;
final double sine = Math.sin(radians);
y1 = (int) (sine * amplitude);
}
}
private static class Ticker extends TimerTask {
private final WavyPanel panel;
Ticker(final WavyPanel panel) {
this.panel = panel;
}
@Override
public void run() {
panel.tick();
}
}
private static class Repainter extends TimerTask {
private final WavyPanel panel;
Repainter(final WavyPanel panel) {
this.panel = panel;
}
@Override
public void run() {
panel.repaint();
}
}
}
呀這是我通常得到的輸出,這個代碼使得輸出變得完美!但是我需要的是那個矩形旋轉一定的角度,並且仍然在相同的Sin Wave中移動。當我使用旋轉時,整個sin波也旋轉,但我只想要矩形旋轉。希望我很清楚。謝謝你的回覆。 – Yash
@Yash我看會更新很快 –
非常感謝:D – Yash