我想使用lucene實現「在文件中查找」類似於IDE中的查找。基本上要搜索源代碼文件,如.c,.cpp,.h,.cs和.xml。我嘗試了在Apache網站上顯示的演示。它返回文件列表,沒有行號和文件中出現的次數。我相信應該有一些方法來獲得它。Lucene可以用行號返回搜索結果嗎?
有無論如何得到這些細節?
我想使用lucene實現「在文件中查找」類似於IDE中的查找。基本上要搜索源代碼文件,如.c,.cpp,.h,.cs和.xml。我嘗試了在Apache網站上顯示的演示。它返回文件列表,沒有行號和文件中出現的次數。我相信應該有一些方法來獲得它。Lucene可以用行號返回搜索結果嗎?
有無論如何得到這些細節?
我試了很多論壇,響應爲零。所以最後我從@Luca Mastrostefano答案得到了一個想法,以獲得行號的細節。
lucene搜索器的Taginfo返回文件名。我認爲這足以獲得行號。 Lucene索引沒有存儲實際的內容,它實際上存儲了散列值。所以不可能直接得到行號。因此,我假設只有使用該路徑並讀取文件並獲取行號。
public static void PrintLines(string filepath,string key)
{
int counter = 1;
string line;
// Read the file and display it line by line.
System.IO.StreamReader file = new System.IO.StreamReader(filepath);
while ((line = file.ReadLine()) != null)
{
if (line.Contains(key))
{
Console.WriteLine("\t"+counter.ToString() + ": " + line);
}
counter++;
}
file.Close();
}
從lucene搜索器的路徑後調用此函數。
請問您可以分享apache網站上顯示的演示鏈接嗎?
在這裏,我告訴你如何得到一個學期給定的文檔的詞頻:
public static void main(final String[] args) throws CorruptIndexException,
LockObtainFailedException, IOException {
// Create the index
final Directory directory = new RAMDirectory();
final Analyzer analyzer = new StandardAnalyzer(Version.LUCENE_36);
final IndexWriterConfig config = new IndexWriterConfig(
Version.LUCENE_36, analyzer);
final IndexWriter writer = new IndexWriter(directory, config);
// addDoc(writer, field, text);
addDoc(writer, "title", "foo");
addDoc(writer, "title", "buz qux");
addDoc(writer, "title", "foo foo bar");
// Search
final IndexReader reader = IndexReader.open(writer, false);
final IndexSearcher searcher = new IndexSearcher(reader);
final Term term = new Term("title", "foo");
final Query query = new TermQuery(term);
System.out.println("Query: " + query.toString() + "\n");
final int limitShow = 3;
final TopDocs td = searcher.search(query, limitShow);
final ScoreDoc[] hits = td.scoreDocs;
// Take IDs and frequencies
final int[] docIDs = new int[td.totalHits];
for (int i = 0; i < td.totalHits; i++) {
docIDs[i] = hits[i].doc;
}
final Map<Integer, Integer> id2freq = getFrequencies(reader, term,
docIDs);
// Show results
for (int i = 0; i < td.totalHits; i++) {
final int docNum = hits[i].doc;
final Document doc = searcher.doc(docNum);
System.out.println("\tposition " + i);
System.out.println("Title: " + doc.get("title"));
final int freq = id2freq.get(docNum);
System.out.println("Occurrences of \"" + term.text() + "\" in \""
+ term.field() + "\" = " + freq);
System.out.println("--------------------------------\n");
}
searcher.close();
reader.close();
writer.close();
}
這裏我們添加文件索引:
private static void addDoc(final IndexWriter w, final String field,
final String text) throws CorruptIndexException, IOException {
final Document doc = new Document();
doc.add(new Field(field, text, Field.Store.YES, Field.Index.ANALYZED));
doc.add(new Field(field, text, Field.Store.YES, Field.Index.ANALYZED));
w.addDocument(doc);
}
這是一個例子如何採取一個文檔術語的occurrencies數量:
public static Map<Integer, Integer> getFrequencies(
final IndexReader reader, final Term term, final int[] docIDs)
throws CorruptIndexException, IOException {
final Map<Integer, Integer> id2freq = new HashMap<Integer, Integer>();
final TermDocs tds = reader.termDocs(term);
if (tds != null) {
for (final int docID : docIDs) {
// Skip to the next docID
tds.skipTo(docID);
// Get its term frequency
id2freq.put(docID, tds.freq());
}
}
return id2freq;
}
如果你把所有的togethe r和你運行它,你就會得到這樣的輸出:
Query: title:foo
position 0
Title: foo
Occurrences of "foo" in "title" = 2
--------------------------------
position 1
Title: foo foo bar
Occurrences of "foo" in "title" = 4
--------------------------------
[鏈接] http://lucene.apache.org/core/4_3_1/demo/overview-summary.html#overview_description – Ganeshkumar
截至目前,我還沒有寫任何代碼。我使用給定的indexfile二進制文件爲一個目錄創建了lucene索引。然後在該索引中搜索一個單詞返回包含該單詞的文件名。但是我需要在這個文件和匹配的行號碼的出現次數上多加一些信息。 – Ganeshkumar
最簡單的解決方案是分別對每行進行索引(使用常見的file_ID和唯一的line_number),執行查詢並檢查結果以提取出現的次數和出現的行數。 否則在這裏[鏈接](http://stackoverflow.com/questions/1311199/finding-the-position-of-search-hits-from-lucene)你可以找到類似你想要的東西。 –