將兩個內部連接查詢組合成一個過程

 SELECT TOP 15 
     us.MxitId AS TransactionCreatedBy, COUNT(t.CreatedBy) Total 
FROM [User] us 
INNER JOIN [Transaction] t ON t.CreatedBy = us.UserId 
Where ChildGender = 'Male' 
GROUP BY us.MxitId, t.ChildGender 
ORDER BY 2 desc 





SELECT TOP 15 
     us.MxitId AS TransactionCreatedBy, COUNT(t.CreatedBy) Total 
FROM [User] us 
INNER JOIN [Transaction] t ON t.CreatedBy = us.UserId 
Where ChildGender = 'Female' 
GROUP BY us.MxitId, t.ChildGender 
ORDER BY 2 desc

我想將上述兩個過程合併爲一個。將兩個內部連接查詢組合成一個過程

請任何人都可以幫助我，我得到的us.MxitId列的重複值。

Select us.MxitId AS TransactionCreatedBy, 
(SELECT TOP 15 
     COUNT(t.CreatedBy) TotalMale where ChildGender = 'Male') , 

      (Select top 15 COUNT(t.CreatedBy) TotalFemale where ChildGender = 'Female') 


    FROM [User] us 
    INNER JOIN [Transaction] t ON t.CreatedBy = us.UserId 

    GROUP BY us.MxitId, t.ChildGender 
    ORDER BY 2 desc

來源

2014-02-25 vini

你想怎樣把它們結合起來？男孩前15名用戶可能與女孩前15名用戶完全不同。或者，它們可以是相同的列表，但順序不同。告訴我們你想要輸出的樣子。 – Anon

嗨用戶是相同的兩種情況下，我想說如果用戶沒有記錄任何女性數據0，或反之亦然 – vini

這個查詢應該努力獲得，而無需重複MxitId的性別統計。

SELECT TOP 15 
     us.MxitId AS TransactionCreatedBy 
, COUNT(t.CreatedBy) AS Total 
, SUM(CASE WHEN ChildGender = 'Female' THEN 1 ELSE 0 END) AS FemaleCount 
, SUM(CASE WHEN ChildGender = 'Male' THEN 1 ELSE 0 END) AS MaleCount 
FROM [User] us 
INNER JOIN [Transaction] t ON t.CreatedBy = us.UserId 
GROUP BY us.MxitId 
ORDER BY 2 desc

來源

2014-02-25 11:52:06 BateTech

在打字前在評論框中說：請避免評論，如+1和謝謝.. ;-) – NickyvV

SELECT TOP 15 
     us.MxitId AS TransactionCreatedBy, 
    sum(case when ChildGender = 'Male' then 1 else 0 end) TotalMale 
     ,sum(case when ChildGender = 'feMale' then 1 else 0 end) TotalFeMale 
FROM [User] us 
INNER JOIN [Transaction] t ON t.CreatedBy = us.UserId 

GROUP BY us.MxitId, t.ChildGender

來源

2014-02-25 11:46:56 KumarHarsh

消息102，級別15，狀態1，行3 '）'附近的語法不正確。 Msg 102，Level 15，State 1，Line 3 'TotalMale'附近語法不正確。 Msg 102，Level 15，State 1，Line 4 'TotalFeMale'附近語法不正確。 – vini

把末尾放在括號內 – KumarHarsh

嗨數據還在重複 – vini

可以使用row_number()做到這一點：

SELECT TransactionCreatedBy, ChildGender, Total 
FROM (SELECT us.MxitId as TransactionCreatedBy, t.ChildGender, COUNT(t.CreatedBy) as Total, 
      row_number() over (partition by t.ChildGender order by COUNT(t.CreatedBy) desc 
           ) as seqnum 
     FROM [User] us INNER JOIN 
      [Transaction] t 
      ON t.CreatedBy = us.UserId 
     GROUP BY us.MxitId, t.ChildGender 
    ) t 
WHERE seqnum <= 15 
ORDER BY Total desc;

我還添加了性別的select列表，以便您可以看到哪些行來自哪個表。

如果你希望把這兩方面在同一個表，然後通過一些措施取前15：

 SELECT us.MxitId as TransactionCreatedBy, COUNT(t.CreatedBy) as Total, 
      sum(case when t.ChildGender = 'Male' then 1 else 0 end) as TotalMales, 
      sum(case when t.ChildGender = 'Female' then 1 else 0 end) as TotalFemales 
     FROM [User] us INNER JOIN 
      [Transaction] t 
      ON t.CreatedBy = us.UserId 
     GROUP BY us.MxitId, t.ChildGender 
     ORDER BY COUNT(t.CreatedBy) desc 
     LIMIT 15;

來源

2014-02-25 11:52:47

寫爲：

select top 15 us.MxitId AS TransactionCreatedBy, 
     count(case ChildGender when 'Male' then 1 else null end) as MaleCount, 
     count(case ChildGender when 'Female' then 1 else null end) as FemaleCount 
from [User] us 
INNER JOIN [Transaction] t ON t.CreatedBy = us.UserId 
GROUP BY us.MxitId

來源

2014-02-25 11:59:13 Deepshikha

將兩個內部連接查詢組合成一個過程

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