我要填寫一個ASP:GridView控件與查詢的結果。我的查詢,有如果「san_proposta.credenciada_id」列在anothers行價值10等於計數特定STATUS_ID的ocurrences數量IF「san_proposta.credenciada_id」的列值10的不同,我需要算具有「credenciada_id」特定STATUS_ID的所有ocurrences等於10邏輯特定計數
我想後續的代碼,但我不知道該怎麼做這個細節計數。
SELECT DISTINCT San_Proposta.Imovel_Id, San_Logradouro.Descricao, San_Endereco.Logradouro, San_Imovel.Numero, San_TipoComplemento.Descricao AS Expr1,
San_Imovel.Complemento, San_Imovel.TipoDsc1, San_Transacao.TransacaoSigla, San_Credenciada.Apelido, San_Transacao.Transacao_ID, COUNT(San_Proposta.StatusProposta_Id) AS NumeroProposta
FROM San_Proposta
JOIN San_Imovel
ON San_Proposta.Imovel_Id = San_Imovel.Imovel_Id
JOIN San_Endereco
ON San_Imovel.Endereco_Id = San_Endereco.Endereco_Id
JOIN San_Logradouro
ON San_Endereco.Logradouro_Id = San_Logradouro.Logradouro_Id
JOIN San_TipoComplemento
ON San_Imovel.TipoComplemento_Id = San_TipoComplemento.TipoComplemento_Id
JOIN San_Transacao
ON San_Imovel.Transacao_ID = San_Transacao.Transacao_ID
JOIN San_Credenciada
ON San_Imovel.Credenciada_Id = San_Credenciada.Credenciada_Id
WHERE (San_Imovel.Credenciada_Id = 10 OR San_Proposta.Credenciada_Id = 10)
GROUP BY San_Proposta.Imovel_Id, San_Logradouro.Descricao, San_Endereco.Logradouro, San_Imovel.Numero,
San_TipoComplemento.Descricao, San_Imovel.Complemento, San_Imovel.TipoDsc1, San_Transacao.TransacaoSigla,
San_Credenciada.Apelido, San_Transacao.Transacao_ID, San_Proposta.StatusProposta_Id,
San_Proposta.Credenciada_Id, San_Imovel.Credenciada_Id
ORDER BY San_Proposta.Imovel_Id DESC
請顯示樣本數據和期望的結果。逆向工程加上有'DISTINCT','GROUP BY'和'COUNT'是非常繁重的查詢詞的問題。 – 2012-02-08 19:21:28