Python：創建顯示兩列之間相同行條目移位的輸出

Question

目標是查看兩列之間的差異，每列包含相同的行條目，僅在不同的行上;

[ 
["ENSCAFG00000008901","ENSCAFG00000013762"], 
["ENSCAFG00000029470","ENSCAFG00000003029"], 
["ENSCAFG00000013782","ENSCAFG00000007249"], 
["ENSCAFG00000000806","ENSCAFG00000012468"], 
["ENSCAFG00000013341","ENSCAFG00000018167"], 
["ENSCAFG00000003376","ENSCAFG00000003376"], 
["ENSCAFG00000000812","ENSCAFG00000018164"], 
["ENSCAFG00000012468","ENSCAFG00000001591"], 
["ENSCAFG00000031786","ENSCAFG00000013782"], 
["ENSCAFG00000000803","ENSCAFG00000030793"], 
["ENSCAFG00000003029","ENSCAFG00000015177"], 
["ENSCAFG00000011565","ENSCAFG00000005750"] 
] 

這個列表有更多的行，所以我不能手工完成。例如，我們在第一列的第11行和第二列的第二行看到ENSCAFG00000003029。我想創建一些輸出，顯示第一列和第二列之間的行相對於第一列的移位。因此，在ENSCAFG00000003029的情況下，我們希望在ENSCAFG00000003029出現在第一列後面的行後面顯示+9（或類似內容）。

我希望我的目標很明確，並且這是提問的正確位置。

Answer 1

我想你必須循環兩次。例如，如果你做的簡化假設，在第一列中的條目都是獨一無二的，你可以這樣做：

cols = [['ENSCAFG00000008901', 'ENSCAFG00000013762'], 
     ['ENSCAFG00000029470', 'ENSCAFG00000003029'], 
     ['ENSCAFG00000013782', 'ENSCAFG00000007249'], 
     ['ENSCAFG00000000806', 'ENSCAFG00000012468'], 
     ['ENSCAFG00000013341', 'ENSCAFG00000018167'], 
     ['ENSCAFG00000003376', 'ENSCAFG00000003376'], 
     ['ENSCAFG00000000812', 'ENSCAFG00000018164'], 
     ['ENSCAFG00000012468', 'ENSCAFG00000001591'], 
     ['ENSCAFG00000031786', 'ENSCAFG00000013782'], 
     ['ENSCAFG00000000803', 'ENSCAFG00000030793'], 
     ['ENSCAFG00000003029', 'ENSCAFG00000015177'], 
     ['ENSCAFG00000011565', 'ENSCAFG00000005750']] 
positions = dict((x[0], i) for i, x in enumerate(cols)) 
[positions[x[1]]-i for i, x in enumerate(cols) if x[1] in positions] 

輸出：

[9, 4, 0, -6] 

Answer 2

l1 =[] 
l2 =[] 
for item in cols: 
    l1.append(item[0]) 
    l2.append(item[0]) 
for item in l1: 
    if item in l2: 
     print str(l2.index(item)) + ':' + str(item) 

Answer 3

它不會非常高效長名單，但這應該工作：

lst = [ 
    ["ENSCAFG00000008901","ENSCAFG00000013762"], 
    ["ENSCAFG00000029470","ENSCAFG00000003029"], 
    ["ENSCAFG00000013782","ENSCAFG00000007249"], 
    ["ENSCAFG00000000806","ENSCAFG00000012468"], 
    ["ENSCAFG00000013341","ENSCAFG00000018167"], 
    ["ENSCAFG00000003376","ENSCAFG00000003376"], 
    ["ENSCAFG00000000812","ENSCAFG00000018164"], 
    ["ENSCAFG00000012468","ENSCAFG00000001591"], 
    ["ENSCAFG00000031786","ENSCAFG00000013782"], 
    ["ENSCAFG00000000803","ENSCAFG00000030793"], 
    ["ENSCAFG00000003029","ENSCAFG00000015177"], 
    ["ENSCAFG00000011565","ENSCAFG00000005750"] 
    ] 

col_1 = [x[0] for x in lst] 
col_2 = [x[1] for x in lst] 

idx_offset = [None] * len(col_1) 
for col_1_idx, val_1 in enumerate(col_1): 
    try: 
     col_2_idx = col_2.index(val_1) 
    except ValueError: 
     continue 
    idx_offset[col_1_idx] = col_2_idx - col_1_idx 

總之，對於第一列中的每個值，找到相同的索引第二列中的值（如果存在）。取這個索引，並從中扣除第一列中的值的索引，這就是你的輸出。輸出（idx_offset）將爲None，用於第一列中不會出現在第二列中的元素。在這種情況下，輸出將變爲：

[None, None, 6, None, None, 0, None, -4, None, None, -9, None]