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我想創建一個工作ID和列的列表,列出所有匹配的不同工作類別,但連接到同一列。作爲一個例子,現在工作82041有兩個類別,但現在返回兩行。我希望它能夠在一個領域內說「零售,銷售助理」。將多行數據合併到同一列
我試過的代碼如下,有人可以告訴我我做錯了什麼嗎?
例:
jobOrderID (No column name)
82027 Motion Graphics
82029 Other
82030 Product Designer
82041 Retail
82041 Sales Associate
82069 Social Media
示例代碼:
select JobOrder.jobOrderID ,
stuff((select distinct ', ' + cast(Category.occupation as nchar(30))
from Category
where Category.categoryID = JobOrderCategories.categoryID
for xml path ('')),1,1,'')
from JobOrder
left outer join JobOrderCategories
on JobOrder.joborderid = JobOrderCategories.jobOrderID
left outer join Category
on Category.categoryID = JobOrderCategories.categoryID
where JobOrder.dateAdded > '2017-5-2' and JobOrder.dateAdded < '2017-5-3'
and joborder.isDeleted = 0
order by joborder.dateAdded asc
學習'format'用'{}你的代碼在'工具欄。 – Parfait
感謝您的注意! –