把python轉換爲php出了問題。我有在python以下代碼:用sha轉換python代碼到php
user = "DdrkmK5uFKmaaeNqfqReMADSUJ4sVSLrV2A8Bvs8"
passing = "K9hvwANSBW5tLYzuWptWMByTtzZZKHzm"
sha = hashlib.sha256()
sha.update(user)
sha.update(passing)
sha_A = [ord(x) for x in sha.digest()]
sha_A
是以下數組:
[231,13,239,136,20,198,76,121,67,163,251, 153,114,13,65,203,41,37,64,168,43,69,81,103,235,161,15,58,82,57,217,178]
我已將其轉換爲php:
$user = "DdrkmK5uFKmaaeNqfqReMADSUJ4sVSLrV2A8Bvs8";
$passing = "K9hvwANSBW5tLYzuWptWMByTtzZZKHzm"
$sha = hash_init("sha256");
$sha = hash_update($sha, $user);
$sha = hash_update($sha, $passing);
$sha_A = [];
$i = 0;
$digest = openssl_digest($sha, "sha256");
$digest = str_split($digest);
foreach ($digest as $x) {
$sha_A[$i] = ord($x);
$i = $i + 1;
}
但是返回的陣列$sha
看起來像這樣:
[101,51,98,48,99,52,52,55,56,102,99,49,99,49,52,57 ,97,102,98,102,52,95,56,57,57,54,102,98,57,50,52]
也許你們中的一些人會發現我的錯誤?
謝謝。這是幫助我:)但以下部分是什麼:sha_A = [在sha.digest()中x的ord(x)]我轉換它是否正確? – razzru80
我也更正了這部分;) –