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閃亮的更新情節在我的示例應用程序我有用戶給一些輸入,並在第一個選項卡中從它生成一個data.table。在第二個選項卡中,我想顯示該圖,具體取決於data.table。我很難獲得正確的反應性。不幸的是在這一點上,我得到了error: Operation not allowed without an active reactive context.
基於data.table
請幫助我或給我提示我做錯了什麼。
數據:
tdata <- data.table(fruit = c("Apple", "Apple", "Apple", "Apple", "Apple", "Apple", "Apple", "Apple","Banana", "Banana","Banana","Banana","Banana", "Banana","Banana","Banana"),
Fertilizer = c(1,2,4,3,2,2,2,2,1,4,3,2,4,4,3,1),
amount = c(2,3,4,7,1,34,33,21,12,32,22,17,14,9,22,6),
red = rep(c("+","+","-","-"),4),
green = rep(c("+","-"),8))
tdata[, grp := do.call(paste, c(list(sep="\n"),.SD)),.SDcols = 4:5]
UI:
library(shiny)
library(data.table)
library(DT)
ui <- (fluidPage(tagList(
sidebarLayout(
sidebarPanel(uiOutput("file_input")),
mainPanel(
tabsetPanel(
tabPanel("Data",dataTableOutput('fruit_table')),
tabPanel("Plot", plotOutput('barPlot'))
))))))
服務器:
server <- function(input, output) {
fileData <- reactive(
return(tdata)
)
output$file_input <- renderUI ({
if(is.null(fileData())){
return()
}else{
tagList(
checkboxGroupInput(inputId = "fruit",
label = "fruit",
choices = c(unique(fileData()[,get("fruit")])),
selected = fileData()[1, 1, with = FALSE]),
checkboxGroupInput(inputId = "tube",
label = "Fertilizer",
choices = unique(fileData()[,get("Fertilizer")]),
selected = fileData()[1, 3, with = F]),
###build checkboxes from Loop:
lapply(1:(length(fileData())-4), function(i) {
checkboxGroupInput(inputId = paste0("color",i),
label = colnames(fileData()[,i+3, with = FALSE]),
choices = c(unique(fileData()[,get(colnames(fileData()[,i+3, with = FALSE]))])),
inline = TRUE,
selected = fileData()[1, i+3, with = FALSE])
}))}})
output$fruit_table <- renderDataTable({
if(is.null(fileData())){
return(NULL)
}else{
validate(
need(input$fruit, 'Check at least one fruit'),
need(input$tube, 'Check at least one Fertilizer'),
####loop not working in here
need(input$color1, "Check at least one !"),
need(input$color2, "Check at least one !")
)
filter_expr <- TRUE
if (!(is.null(input$fruit))) {
filter_expr <- filter_expr & fileData()[,fruit] %in% input$fruit
#print((input$fruit))
}
if (!(is.null(input$tube))) {
filter_expr <- filter_expr & fileData()[,Fertilizer] %in% input$tube
}
##non-loop-verison
if (!(is.null(input$color1))) {
filter_expr <- filter_expr & fileData()[,red] %in% input$color1
}
if (!(is.null(input$color2))) {
filter_expr <- filter_expr & fileData()[,green] %in% input$color2
}
datatable(fileData()[filter_expr,],options = list(pageLength = 25))
}})
plot.dat <- reactiveValues(main = NULL)
plot.dat$main <- ggplot(data = fileData(), mapping = aes(x = fileData()[,grp], y =fileData()[,amount]))+
geom_boxplot(stat = 'boxplot',
position = position_dodge(width=0.8),
width = 0.55)
observe({
output$barPlot <- renderPlot({
if(is.null(fileData())){
return(NULL)
}else{
validate(
need(input$fruit, 'Check at least one fruit'),
need(input$tube, 'Check at least one Fertilizer'),
need(input$color1, "Check at least one !"),
need(input$color2, "Check at least one !")
)
plot.dat$main
}})
})
}
shinyApp(ui = ui, server = server
)
我不確定我是否正確理解它,但在renderPlot中調用fileData()並不意味着在那裏創建它。現在,當輸入發生變化時,情節會刷新,但情節不會改變。 – Rivka
調用fileData()只是返回數據表'tdata'(這是你如何定義它)。如果你想根據輸入改變輸出,改變'fileData < - reactive ...'定義中的'tdata' :) – shosaco
你能舉個例子嗎?我認爲fileData()已經被動了。如果它沒有反應,數據選項卡中顯示的data.table將如何更改? – Rivka