如何將變量傳遞給新的孩子？ [flash AS3]

Question

該代碼很好地說明了這個問題，我將所有不相關的東西都刪除了。

創建2-4親屬當比賽開始

function createInitialKinsmen() 
{ 
    for (var k:int = 1; k < 3 + Math.round(Math.random() * 2; k++) 
    { 
     if (k == 1) 
     { 
      createKinsmen(0); 
      trace ("player"); 
     } 
     else 
     { 
      createKinsmen(1); 
      trace ("starting kinsmen"); 
     } 
    } 
} 

男性親屬創建功能

function createKinsmen(arrivalTypeVar:int) 
{ 
    var newKinsmen = new kinsmen; 
    listPanel.kinsmenDivider.addChild(newKinsmen); 
    totalKinsmen++; 
    totalKinsmenAlive++; 
    newKinsmen.name = "kinsmen" + totalKinsmen; 
    newKinsmen.arrivalType = arrivalTypeVar; 
} 

男性親屬類

public class kinsmen extends MovieClip 
{ 
    var arrivalType:int; 
    function kinsmen() 
    { 
     trace(this.name); 
     if (this.arrivalType = 0) 
     { 
      trace("player"); 
     } 
     if (this.arrivalType = 1) 
     { 
      trace("starting kinsmen"); 
     } 
    } 
} 

輸出應該說：

kinsmen1 
player 
player 
kinsmen2 
starting kinsmen 
starting kinsmen 
kinsmen3 
starting kinsmen 
starting kinsmen 
kinsmen4 
starting kinsmen 
starting kinsmen 

但是相反說：

kinsmen1 
player 
player 
kinsmen2 
player 
starting kinsmen 
kinsmen3 
player 
starting kinsmen 
kinsmen4 
player 
starting kinsmen 

這意味着，arrivalType變量沒有被通過。這似乎是硬編碼的變量可以通過，因此，此刻我有一個與alpha 0在親族動畫片內的正方形，它的x位置決定了arrivalType在構造函數中的值，但這肯定不是好的做法，有沒有更好的方法來做到這一點？

Answer 1

我想你只是想修改kinsmen類的構造函數來接受arrivalType和name的參數。

你目前正在做的是構造一個新的kinsmen對象，然後在該對象上設置arrivalType和name。因此，構造函數代碼運行時，該arrivalType是int的默認值是0

修改你的構造函數，這樣在kinsmen類：

function kinsmen(arrivalType:int, name:String) 
{ 
    this.name = name; 
    this.arrivalType = arrivalType; 
    if (this.arrivalType == 0) 
    { 
     trace("player"); 
    } 
    if (this.arrivalType == 1) 
    { 
     trace("starting kinsmen"); 
    } 
} 

和修改createKinsmen()功能，使其通過在用於arrivalType給構造方法的值，而不是設置arrivalType和name對象之後被創建：

function createKinsmen(arrivalTypeVar:int) 
{ 
    totalKinsmen++; 
    totalKinsmenAlive++; 
    var newKinsmen = new kinsmen(arrivalTypeVar, "kinsmen" + totalKinsmen); 
    listPanel.kinsmenDivider.addChild(newKinsmen); 
}