我有一個函數上的數組的數組(allArr),來自allArr的位置0的第一個時間數組與從另一個數組與圖像(名爲image)然後通過點擊一個按鈕(id =「nextimageandshuffle」)數組從allArr和圖像數組中的圖像達到第五。我的問題是,每次我點擊下一個按鈕,我必須用清空()div(id =「數組「),其中allArr的數組添加了append(),但我無法在第5個數組之後停止,因此第5個圖像(來自圖像數組)仍保留在那裏,但第5個數組(從allArr)刪除了它...如何結束.empty()
繼承人my代碼:
var allArr;
var contor = 0;
var i = 0;
$(document).ready(function() {
var arr = new Array("images/alfabet/w.png", "images/alfabet/f.png", "images/alfabet/v.png", "images/alfabet/a.png", "images/alfabet/b.png", "images/alfabet/p.png", "images/alfabet/o.png", "images/alfabet/r.png");
var baiat = new Array("images/alfabet/p.png", "images/alfabet/b.png", "images/alfabet/a.png", "images/alfabet/aa.png", "images/alfabet/i.png","images/alfabet/a.png", "images/alfabet/t.png");
var colac = new Array("images/alfabet/g.png", "images/alfabet/c.png", "images/alfabet/u.png", "images/alfabet/o.png", "images/alfabet/l.png", "images/alfabet/a.png", "images/alfabet/c.png");
var slapi = new Array("images/alfabet/s.png", "images/alfabet/ss.png", "images/alfabet/l.png", "images/alfabet/a.png", "images/alfabet/b.png", "images/alfabet/p.png", "images/alfabet/i.png", "images/alfabet/i.png");
var umbrela = new Array("images/alfabet/u.png", "images/alfabet/n.png", "images/alfabet/m.png", "images/alfabet/p.png", "images/alfabet/b.png", "images/alfabet/r.png", "images/alfabet/e.png", "images/alfabet/l.png", "images/alfabet/a.png");
allArr = new Array(arr, baiat, colac, slapi, umbrela);
for(i=0; i<allArr[0].length; i++)
{
var img = new Image();
img.src = allArr[0][i];
$('#array').append(img);
}
});
var image = new Array("images/baiat.png", "images/colac.png" , "images/slapi.png" , "images/umbrela.png");
var imgNumber=0;
var numberOfImg = image.length;
function nextImage(){
if(imgNumber < numberOfImg){
imgNumber++;
}
document.slideImage.src = image[imgNumber-1];
contor++;
$("#array").empty();
for(i = 0; i<allArr[contor].length; i++)
{
var img = new Image();
img.src = allArr[contor][i];
$('#array').append(img);
}
}
if(document.images){
var image1 = new Image();
image1.src = "images/vapor.png";
var image2 = new Image();
image2.src = "images/baiat.png";
var image3 = new Image();
image3.src = "images/colac.png";
var image4 = new Image();
image4.src = "images/slapi.png";
var image5 = new Image();
image5.src = "images/umbrela.png";
}
HTML:
<img src="images/vapor.png" name="slideImage" class='secondcanvas' width='450' height='300' alt="">
<div id="array" class='thirdcanvas'></div>
<a href="#" onClick="nextImage()"><img id="nextimageandshuffle" src="images/nextBtn.png" title="Continuare" ></a>
很酷,我忘了添加其他的時候,當我想用if,但我的和你的if不工作......我們必須等於圖像陣列的最後位置圖像最後一個數組名爲umbrela allArr ...如果我們單擊下一個直到umbrela數組,停止.empty()else do.empty() – OzZie
啊,我明白了,當我最初讀它時,我想你在每次點擊「下一步」時都會動態地拉動圖像。如果在文檔加載時它們全部被填充,則您需要搶佔該位置。很高興我能幫上忙! – Ant
我想出瞭如何做到這一點,我作出了contor在第四陣列後結束的條件,所以,從現在開始,即使我點擊next..can't後去第四個數組:D – OzZie