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我遇到了SQL SELECT語句的問題,我在Google和youtube上搜索過,但是我什麼也沒找到。Select Statement正在加載錯誤的數據
這是我的PHP代碼:
public function loadMark($data){
dbConn();
$query = "SELECT
subject.subName
, mark.mark
FROM
itcollage.marktype
, itcollage.student
INNER JOIN itcollage.parent
ON (student.pId = parent.pId)
INNER JOIN itcollage.mark
ON (mark.stId = student.sId)
INNER JOIN itcollage.subject
ON (mark.subId = subject.subId)
WHERE
parent.pUsername='$data'
AND
mark.subId = subject.subId LIMIT 2";
return $result= mysql_query($query);
}
,我wan't這個加載正確標記爲拿到學生ID的父母,但它不斷重複的痕跡所有科目。
數據如下:
Subject Mark
-------- | ------
Java 101 | A
Java 101 | D
Math 101 | A
Math 101 | D
- 的Java 101 = A,數學= d
所以,什麼是錯!
這裏是我的調用類marks.class.php
include '../classes/mark.class.php';
$mark = new mark();
$result = $mark->loadMark($user);
$num = mysql_num_rows($result);
if ($num == 0) {
?>
<h2>No Marks for your Kid</h2>
<?php
} else {
?>
<h2>Marks</h2>
<table>
<thead>
<tr>
<th>Subject</th>
<th>Mark</th>
</tr>
</thead>
<tbody>
<?php
while ($row = mysql_fetch_object($result)) {
$marks = $row->mark;
$subject = $row->subName;
?>
<tr class="light">
<td align="center"><?php echo $subject; ?></td>
<td align="center"><?php echo $marks; ?></td>
</tr>
<?php
}
?>
</tbody>
</table>
誰能告訴我什麼是錯誤的代碼?
看來你有一些語法錯誤在FROM子句 – veljasije 2013-03-24 22:59:39
以及如何解決內部連接語句加載你的隊友重播:) – 2013-03-24 23:03:10
嘗試正確的數據和THX避免INNER JOIN與標記或標記類型表,因爲它可以創建重複。並把表格數據的樣本。 – veljasije 2013-03-24 23:12:25