如何構建一個包含文件夾結構的數組？

Question

我想構建一個Json輸出來列出ExtJS樹面板中的文件夾結構。的結構應該是這樣的陣列的使用JSON的當量：

Array 
(
    [text] => . 
    [children] => Array 
     (
      [0] => Array 
       (
        [text] => files 
        [children] => 
       ) 

      [1] => Array 
       (
        [text] => folder 1 
        [children] => 
       ) 

      [2] => Array 
       (
        [text] => New directory 
        [children] => array(
         [0] => Array 
          (
           [text] => sub_1 
           [children] => array(
            [0] => Array 
             (
              [text] => sub_1_1 
              [children] => 
             ) 
            [1] => Array 
             (
              [text] => sub_1_2 
              [children] => 
             )          
           ) 
          ) 
         [1] => Array 
          (
           [text] => sub_2 
           [children] => 
          )        
        ) 
       )  
     )  
) 

我提出這個函數通過PHP手冊打算示出的結構和實施例

listFolders('../file_uploads/'); 
function listFolders($dir){ 
    $dh = scandir($dir); 
    echo '<ul>'; 
    foreach($dh as $folder){ 
     if($folder != '.' && $folder != '..') 
     { 
      if(is_dir($dir.'/'.$folder)){ 
       echo '<li>'.$folder.'</li>'; 
       listFolders($dir.'/'.$folder); 
      } 
     } 
    } 
    echo '</ul>'; 
} 

此輸出結構

• 新目錄
• sub_1
• sub_1_1
個
• sub_1_1_1
• sub_1_2
• sub_2
• 文件
• 文件夾1

我想知道如何將這個輸出轉換爲陣列（或JSON的）像上面一樣？

溶液

print "<pre>"; 
print_r(listFolders('../file_uploads/')); 

function listFolders($dir) 
{ 
    $dh = scandir($dir); 
    $return = array(); 

    foreach ($dh as $folder) { 
     if ($folder != '.' && $folder != '..') { 
      if (is_dir($dir . '/' . $folder)) { 
       $return[] = array(
        'text' => $folder, 
        'children' => listFolders($dir . '/' . $folder) 
       ); 
      } 
     } 
    } 
    return $return; 
} 

Answer 1

試試下面的代碼：

function listFolders($dir) 
{ 
    $dh = scandir($dir); 
    $return = array(); 

    foreach ($dh as $folder) { 
     if ($folder != '.' && $folder != '..') { 
      if (is_dir($dir . '/' . $folder)) { 
       $return[] = array($folder => listFolders($dir . '/' . $folder)); 
      } else { 
       $return[] = $folder; 
      } 
     } 
    } 
    return $return; 
} 

似乎爲我工作，沒有測試但正常。

Answer 2

首先創建一個數組。對於每個創建的目錄，使用array_push到數組？

也看看http://php.net/manual/en/function.scandir.php的意見。

Answer 3

<?php 
error_reporting(0); 

$array_folders = listFolders('../file_uploads/'); 
echo "<pre>"; 
print_r($array_folders); 

function listFolders($dir){ 
    global $ret_array; 
    $dh = scandir($dir); 
    foreach($dh as $folder){ 
     if($folder != '.' && $folder != '..') 
     { 
      if(is_dir($dir.'/'.$folder)){ 
       $ret_array[$dir][] = $folder; 
       listFolders($dir.'/'.$folder); 
      } 
     } 
    } 
    return $ret_array; 
} 
?> 

Answer 4

我想你正在尋找一個遞歸目錄列表。使用下面的代碼我希望它能幫助你。這個對我有用。

<?php 
/** 
* Function for recursive directory file list search as an array. 
* 
* @param mixed $dir Main Directory Path. 
* 
* @return array 
*/ 
function listFolderFiles($dir) 
{ 
    $fileInfo  = scandir($dir); 
    $allFileLists = []; 

    foreach ($fileInfo as $folder) { 
     if ($folder !== '.' && $folder !== '..') { 
      if (is_dir($dir . DIRECTORY_SEPARATOR . $folder) === true) { 
       $allFileLists[$folder . '/'] = listFolderFiles($dir . DIRECTORY_SEPARATOR . $folder); 
      } else { 
       $allFileLists[$folder] = $folder; 
      } 
     } 
    } 

    return $allFileLists; 
}//end listFolderFiles() 


$dir = listFolderFiles('your searching directory path ex:-F:\xampp\htdocs\abc'); 
echo '<pre>'; 
print_r($dir); 
echo '</pre>' 

?> 

Answer 5

要得到完全相同的結果就可以了，跟着婁代碼

function listFolderFiles($dir){ 
    $ffs = scandir($dir); 

    unset($ffs[array_search('.', $ffs, true)]); 
    unset($ffs[array_search('..', $ffs, true)]); 

    // prevent empty ordered elements 
    //if (count($ffs) < 1) 
    // return; 


    $dirStrArr = array(); 
    foreach($ffs as $ff){ 
     if(is_dir($dir.'/'.$ff)) { 
      $dirStrArr[]=array('parent' => $ff, 'children' => listFolderFiles($dir . '/' . $ff)); 
     }else{ 
      $dirStrArr[]=$ff; 
     } 
    } 
    return $dirStrArr; 
} 

或獲得的文件夾名稱作爲索引和索引的數組中的孩子的細節，你可以按下面的代碼

function listFolderFiles($dir){ 
    $ffs = scandir($dir); 

    unset($ffs[array_search('.', $ffs, true)]); 
    unset($ffs[array_search('..', $ffs, true)]); 

    // prevent empty ordered elements 
    //if (count($ffs) < 1) 
    // return; 


    $dirStrArr = array(); 
    foreach($ffs as $ff){ 
     if(is_dir($dir.'/'.$ff)) { 
      $dirStrArr[$ff]=listFolderFiles($dir . '/' . $ff); 
     }else{ 
      $dirStrArr[]=$ff; 
     } 
    } 
    return $dirStrArr; 
}