如何使用MySQL的查詢

Question

車輛

+--------------------+--------------+------+-----+---------+ 
| Field    | Type   | Null | Key | Default | 
+--------------------+--------------+------+-----+---------+ 
| id     | int(11)  | NO | Pk | NULL |  
| model    | varchar(35) | NO |  | NULL |    
+--------------------+--------------+------+-----+---------+ 

信息

+--------------------+--------------+------+-----+---------+ 
| Field    | Type   | Null | Key | Default | 
+--------------------+--------------+------+-----+---------+ 
| id     | int(11)  | NO | Pk | NULL |  
| vehicle_id   | varchar(35) | NO | FK | NULL |  
| location   | varchar(35) | NO |  | NULL |  
+--------------------+--------------+------+-----+---------+ 

車橋1

+--------------------+--------------+------+-----+---------+ 
| Field    | Type   | Null | Key | Default | 
+--------------------+--------------+------+-----+---------+ 
| id     | int(11)  | NO | Pk | NULL |  
| vehicle_id   | varchar(35) | NO | FK | NULL |  
| weight    | varchar(35) | NO |  | NULL |  
+--------------------+--------------+------+-----+---------+ 

車橋2

+--------------------+--------------+------+-----+---------+ 
| Field    | Type   | Null | Key | Default | 
+--------------------+--------------+------+-----+---------+ 
| id     | int(11)  | NO | Pk | NULL |  
| vehicle_id   | varchar(35) | NO | FK | NULL |  
| weight    | varchar(35) | NO |  | NULL |  
+--------------------+--------------+------+-----+---------+ 

我鏈接4桌希望創建一個查詢，該查詢將返回具有常見vehicle_id的所有表中的所有字段。 vehicle_id是車輛表中主鍵的3個表格（信息，車軸1，車軸2）中的每一個的參考。有人可以解釋我可能會這樣做嗎？我嘗試使用多個連接，但它沒有工作！非常感謝。

編輯：

我試過的查詢是;

SELECT * 
     FROM Vehicle 
     JOIN info, axle1, axle 2 
     ON vehicle.id = axle1.vehicle_id 
    AND vehicle.id = axle2.vehicle_id AND vehicle.id = info.vehicle_id 

Answer 1

試試這個：

SELECT * 
FROM Vehicle v 
INNER JOIN Info i ON   v.id = i.vehicle_id 
INNER JOIN Axle1 a1 ON i.vehicle_id = a1.vehicle_id 
INNER JOIN Axle2 a2 ON a1.vehicle_id = a2.vehicle_id 

Answer 2

檢查此鏈接：mySQL get information from multiple tables in one query我認爲有可能適應的例子

你只需要爲每個表的標識，以便您可以指定你在談論某個領域時談論哪個表格。然後，確保將所有ID鏈接爲條件，以便省略標識符不匹配的所有組合。那將是：

SELECT * FROM Vehicle v, Info i, Axle1 a1, Axle2 a2 WHERE v.id == a1.vehicle_id AND v.id == a2.vehicle_id AND v.id == i.vehicle_id