蟒正則表達式的子％H：％M：％S到％M：％S或01：％M：％S

Question

我想從字符串轉換（字幕）：

585 
00:59:59,237 --> 01:00:01,105 
- It's all right. - He saw us! 

586 
01:00:01,139 --> 01:00:03,408 
I heard you the first time. 

成

59:59 - 沒關係。 - 他看到我們了！

01:00:01我第一次聽到你。

* 我要的是：如果時間是一個小時內，剪掉了「00」的前綴，而保持它，如果時間大於1小時*

我正則表達式是：

pat = re.compile(r""" 
    #\s*     # Skip leading whitespace 
    \d+\s     # remoe lines contain only numbers 
    ((?:(?:00)|(?P<hour>01)):(?P<time>\d{2}:\d{2})[,0-9->]+.*)[\r\n]+(?P<content>.*)[\r\n]+ 
    """, 
    re.VERBOSE) 
data = pat.sub(r"\g<hour>\g<time> \g<content>", data) 

只有當'\g<hour>'沒有被使用時它纔會起作用。 任何人都可以幫助我嗎？

Answer 1

我想，這是你在找什麼：

import re 

s = """ 
585 
00:59:59,237 --> 01:00:01,105 
- It's all right. - He saw us! 

586 
01:00:01,139 --> 01:00:03,408 
I heard you the first time. 
""" 

for line in re.findall(r'(\d+:)(\d+:\d+)(?:.*\n)(.*)', s): 
    if line[0] == '00:': 
     print ' '.join(line[1:]) 
    else: 
     print ' '.join([''.join(line[0:2]), line[2]]) 

輸出：

# 59:59 - It's all right. - He saw us! 
# 01:00:01 I heard you the first time. 

Answer 2

只是給非重的方法（這應該是更快）：

a = """585 
00:59:59,237 --> 01:00:01,105 
- It's all right. - He saw us! 

586 
01:00:01,139 --> 01:00:03,408 
I heard you the first time.""" 

for i, x in enumerate(a.split('\n')): 
    m = i % 4 
    if m == 0: 
     continue 
    elif m == 3: 
     continue 
    elif m == 1: 
     print x[:x.find(":", x.find(":") + 1)], 
    elif m == 2: 
     print x