如何在SQL查詢中顯示多個表中的列？

Question

我試圖顯示從我的查詢中有3個表中的一個列中的列，但我似乎無法弄清楚如何讓它正常工作。無論我嘗試什麼，它似乎都不起作用。這似乎很容易，但也許我錯過了一些非常簡單的事情。以下是我有：

SELECT hpg.id_number, 
    hpg.id_description, 
    COUNT (hdd.number_of_games) games, 
    SUM (NVL (price, 0)) total, 
    SUM (number_of_food) food 
--I tried adding column here, but nothing seemed to work 
FROM (SELECT number_of_games, price, prints 
     FROM (hopeful_dog_hops) 
     WHERE status = 'Done') hdd, 
    (SELECT SUM (number_of_food) number_of_food, number_of_games 
      FROM hot_digity_dog 
     GROUP BY number_of_games) hdd1, 
    (SELECT id_description, sort_types, id_number 
     FROM (hot_pick_games) 
     WHERE disabled = 'TRUE' AND viewable_type = 'OK') hpg 
WHERE hdd.prints(+) = hpg.id_number 
    AND hdd.number_of_games = hdd1.number_of_games 
GROUP BY hpg.id_description, hpg.id_number, sort_types 
ORDER BY sort_types 

這個巨大的查詢顯示這些列：

ID_NUMBER ID_DESCRIPTION GAMES TOTAL FOOD 

我需要增加一個列：從hot_digity_dog表

TEST 

。

不要太擔心所有事情的名稱，但我只需要弄清楚我到底能夠在查詢中顯示另一列。我試着將TEST添加到第一個SELECT語句中，但它給了我一個錯誤：「TEST：無效標識符」。

我知道查詢的工作原理（沒有添加TEST部分，所以它不能成爲查詢中的錯誤）。它必須是新增加的部分。

任何幫助將不勝感激。提前致謝。

這裏是新列的查詢：

SELECT hpg.id_number, 
    hpg.id_description, 
    COUNT (hdd.number_of_games) games, 
    SUM (NVL (price, 0)) total, 
    SUM (number_of_food) food, 
    hdd.TEST 
FROM (SELECT number_of_games, price, prints 
     FROM (hopeful_dog_hops) 
     WHERE status = 'Done') hdd, 
    (SELECT SUM (number_of_food) number_of_food, number_of_games 
      FROM hot_digity_dog 
     GROUP BY number_of_games) hdd1, 
    (SELECT id_description, sort_types, id_number 
     FROM (hot_pick_games) 
     WHERE disabled = 'TRUE' AND viewable_type = 'OK') hpg 
WHERE hdd.prints(+) = hpg.id_number 
    AND hdd.number_of_games = hdd1.number_of_games 
GROUP BY hpg.id_description, hpg.id_number, sort_types 
ORDER BY sort_types 

這裏是列標題應該是什麼樣子：

ID_NUMBER ID_DESCRIPTION GAMES TOTAL FOOD TEST 

Answer 1

的問題是，你是不是從hot_digity_dog的選擇外部查詢。您可以從基於該表的AGGREGATE子查詢中進行選擇 - 您以別名hdd1作爲別名的子查詢。所以，目前尚不清楚如何你想添加那個列。 test完全由number_of_games決定？如果是，則可以將test添加到聚合子查詢的select和group by子句中，然後可以在外部查詢中選擇它。

如果test不是由number_of_games確定，你要總結number_of_food由number_of_games和test爲分組？如果是這樣，再次在子查詢中添加test到select和group by（但結果將單獨由number_of_games分組）。

如果test不是由number_of_games確定，要通過組爲number_of_games的總和，但要顯示test無論如何，你可能需要使用分析sum()而不是總sum()。

這只是一個小例子，向您證明您發佈的內容不足以讓我們來幫助您。請提供（更多）更多細節 - 通過編輯原始問題，而不是在評論中。

Answer 2

我認爲你只是缺少在HDD查詢測試柱：

SELECT hpg.id_number, 
    hpg.id_description, 
    COUNT (hdd.number_of_games) games, 
    SUM (NVL (price, 0)) total, 
    SUM (number_of_food) food, 
    hdd.TEST 
FROM (SELECT number_of_games, price, prints, TEST 
     FROM (hopeful_dog_hops) 
     WHERE status = 'Done') hdd, 
    (SELECT SUM (number_of_food) number_of_food, number_of_games 
      FROM hot_digity_dog 
     GROUP BY number_of_games) hdd1, 
    (SELECT id_description, sort_types, id_number 
     FROM (hot_pick_games) 
     WHERE disabled = 'TRUE' AND viewable_type = 'OK') hpg 
WHERE hdd.prints(+) = hpg.id_number 
    AND hdd.number_of_games = hdd1.number_of_games 
GROUP BY hpg.id_description, hpg.id_number, sort_types 
ORDER BY sort_types