2012-11-09 44 views
1

我已經編寫了以下webworker,它將處理圖像並將雙線性插值添加到放大版本。在純Javascript中縮小圖像

這對於使圖像更大很好,但我現在需要使圖像變小。

我的理解是插值是爲了不縮小尺寸而進行放大。

this.addEventListener('message', function(event) { 

    var src = event.data.imageData, 
     dest = event.data.imageDataNew 

     postMessage({ 
      'imageData':bilinear(src, dest, scale) 
     }); 

}, false); 

    function ivect(ix, iy, w) { 
     // byte array, r,g,b,a 
     return((ix + w * iy) * 4); 
    } 

function bilinear(srcImg, destImg, scale) { 
     // c.f.: wikipedia english article on bilinear interpolation 
     // taking the unit square, the inner loop looks like this 
     // note: there's a function call inside the double loop to this one 
     // maybe a performance killer, optimize this whole code as you need 
     function inner(f00, f10, f01, f11, x, y) { 
      var un_x = 1.0 - x; var un_y = 1.0 - y; 
      return (f00 * un_x * un_y + f10 * x * un_y + f01 * un_x * y + f11 * x * y); 
     } 
     var i, j; 
     var iyv, iy0, iy1, ixv, ix0, ix1; 
     var idxD, idxS00, idxS10, idxS01, idxS11; 
     var dx, dy; 
     var r, g, b, a; 
     for (i = 0; i < destImg.height; ++i) { 
      iyv = i/scale; 
      iy0 = Math.floor(iyv); 
      // Math.ceil can go over bounds 
      iy1 = (Math.ceil(iyv) > (srcImg.height-1) ? (srcImg.height-1) : Math.ceil(iyv)); 
      for (j = 0; j < destImg.width; ++j) { 
       ixv = j/scale; 
       ix0 = Math.floor(ixv); 
       // Math.ceil can go over bounds 
       ix1 = (Math.ceil(ixv) > (srcImg.width-1) ? (srcImg.width-1) : Math.ceil(ixv)); 
       idxD = ivect(j, i, destImg.width); 
       // matrix to vector indices 
       idxS00 = ivect(ix0, iy0, srcImg.width); 
       idxS10 = ivect(ix1, iy0, srcImg.width); 
       idxS01 = ivect(ix0, iy1, srcImg.width); 
       idxS11 = ivect(ix1, iy1, srcImg.width); 
       // overall coordinates to unit square 
       dx = ixv - ix0; dy = iyv - iy0; 
       // I let the r, g, b, a on purpose for debugging 
       r = inner(srcImg.data[idxS00], srcImg.data[idxS10], 
        srcImg.data[idxS01], srcImg.data[idxS11], dx, dy); 
       destImg.data[idxD] = r; 

       g = inner(srcImg.data[idxS00+1], srcImg.data[idxS10+1], 
        srcImg.data[idxS01+1], srcImg.data[idxS11+1], dx, dy); 
       destImg.data[idxD+1] = g; 

       b = inner(srcImg.data[idxS00+2], srcImg.data[idxS10+2], 
        srcImg.data[idxS01+2], srcImg.data[idxS11+2], dx, dy); 
       destImg.data[idxD+2] = b; 

       a = inner(srcImg.data[idxS00+3], srcImg.data[idxS10+3], 
        srcImg.data[idxS01+3], srcImg.data[idxS11+3], dx, dy); 
       destImg.data[idxD+3] = a; 
      } 
     } 

     return destImg; 
    } 

我還寫了一個Lancosz webworker,它產生了很好的結果,但是速度很慢。我正在尋找的東西是介於兩者之間的東西。

有誰知道雙線性/雙立體縮小過濾器的合理快速的JavaScript實現嗎?

我將要處理的圖像種類可能會大到5000x5000,並會縮小到1000x1000。

只要性能低於10秒左右就可以了。

+0

(在JS遊戲男孩彩色仿真器的作者)和縮放圖像來與本地帆布的drawImage ISN可以接受嗎? – Shmiddty

+0

不幸的是,當從5000x5000px到1000x1000px時,縮小圖像看起來相當差 – gordyr

回答