禁用的IBAction爲聯按鈕

Question

我使用界面生成器做了一個按鈕，並將其鏈接到一個動作。我想禁用砸在下面的if聲明按鈕。

- (IBAction)hit:(id)sender { 
    Application *app = [[Application alloc] init]; 
    int nc = [app dealCard]; 
    [userOne setIntValue:tu]; 
    [userTwo setIntValue:nc]; 
    tu += nc; 
    [totalUser setIntValue:tu]; 
    BOOL bust = [app checkBust:tu]; 
    if (bust == YES) { 
     [console setIntValue:1]; 
     //Disable button here. 
    } 
} 

我該怎麼辦？

Answer 1

我發現了這個問題。事實證明，我是用NSButton代替UIButton所以我改變了聲明：NSButton *theButton = (NSButton *)sender;。

然後我更換theButton.enabled = NO;到[theButton setEnabled = NO];。

因此，這裏是我完成的代碼：

- (IBAction)hit:(id)sender { 
    Application *app = [[Application alloc] init]; 
    NSButton *theButton = (NSButton *)sender; 
    int nc = [app dealCard]; 
    [userOne setIntValue:tu]; 
    [userTwo setIntValue:nc]; 
    tu += nc; 
    [totalUser setIntValue:tu]; 
    BOOL bust = [app checkBust:tu]; 
    if (bust == YES) { 
     [console setIntValue:1]; 
     [theButton setEnabled = NO]; 
    } 
} 

Answer 2

UIButton是UIResponder的子類，它具有enabled屬性。將其設置爲NO以禁用按鈕中的操作。例如。

UIButton *theButton = (UIButton *)sender; 
theButton.enabled = NO;