我有一個INSERT語句,後面跟着一個SQLITE3_EXEC,後面跟着一個SELECT語句和另一個SQLITE3_EXEC。我在SELECT語句的EXEC上得到了一個SQLERROR 21(SQLITE_MISUSE)。INSERT語句後需要什麼?
我錯過了兩個EXEC之間的東西嗎?像一個COMMIT,或?
21是否可能試圖插入已存在的記錄?
NSString *insertCommand = [NSString stringWithFormat:@"INSERT INTO CardData (CARD_ID, CARD_NAME, CODE_VAL) VALUES ('/%@', '/%@', '/%@')",
symbol.data, @"Test Card", symbol.typeName];
sqlite3_exec(db, [insertCommand UTF8String], NULL, NULL, &errmsg);
if(errmsg != NULL)
NSLog(@"insert error: /%@", &errmsg); // DEBUGGING ONLY!
// now, pull it back out of the d/b and display the data
const char *sqlStatement = @"select CARD_ID, CARD_NAME, CODE_VAL from CardData";
sqlite3_stmt *compiledStatement;
int err = sqlite3_prepare_v2(db, [sqlStatement UTF8String], -1, &compiledStatement, NULL); // Setup the SQL Statement and compile it for faster access
if(err != SQLITE_OK)
NSLog(@"prepare error: /%@", err);
else {
// Loop through the results and add them to the feeds array
while(sqlite3_step(compiledStatement) == SQLITE_ROW) {
// Read the data from the result row
resultText.text = [NSString stringWithFormat:@"\nDatabase: \n%@ \n%@ \n%@", resultText.text,
[NSString stringWithUTF8String:(char *)sqlite3_column_text(compiledStatement, 0)],
[NSString stringWithUTF8String:(char *)sqlite3_column_text(compiledStatement, 1)],
[NSString stringWithUTF8String:(char *)sqlite3_column_text(compiledStatement, 2)]];
}
sqlite3_finalize(compiledStatement); // release it...
sqlite3_close(db);
}
你爲什麼不提供你正試圖執行的SQL語句? – 2011-05-02 17:00:49
這裏是... http://monobin.com/__d215dc84d – SpokaneDude 2011-05-02 17:09:20
夥計。在問題中發佈相關文字。 – Joe 2011-05-02 17:20:35